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Anna35 [415]
3 years ago
15

In our usual coordinate system( +x to the right, +y up (away from the center of the Earth), +z out of the page toward you), what

is the vector gravitational force on a 31 kg object sitting on the ground? (From the momentum principle you can conclude that a force of the same magnitude is exerted upward by the ground on the object if the momentum isn't changing. In Chapter 4 we'll see more about the origin of this force.)
Physics
1 answer:
skad [1K]3 years ago
5 0

Answer:

The vector gravitational force is  W = 303.8\  N( -y)

Explanation:

From the question we are told that

      The mass of the object is  m  = 31 \ kg

      The acceleration due to gravity experienced by the object is g =  9.8 m/s^2

Generally the vector gravitational force on the object is mathematically represented as

                       W = 31 *  9.8

                       W = 303.8\  N (-y)

The  -y indicates that the direction of the force is towards the center of the earth

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Answer:

Hello your question is incomplete attached below is the complete question and solution

<em>answer; </em>

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Explanation:

<em>Given data:</em>

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3 years ago
when a man throws a stone in the direction of maximum range the stone rises to a height of 20m . what is the range and how long
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Answer:

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3 years ago
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german

Answer:

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2 years ago
In an inkjet printer, letters and images are created by squirting drops of ink horizontally at a sheet of paper from a rapidly m
Serga [27]

Answer:

q = 6.48 \times 10^{-14} C

Explanation:

Deflection in the drop is due to electric field force

so we will have

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acceleration of the drop is given as

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0.310 \times 10^{-3} = 4.78 \times 10^9 q

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3 years ago
What is the minimum amount of data points an experiment should gather?
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3 years ago
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