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Anna35 [415]
3 years ago
15

In our usual coordinate system( +x to the right, +y up (away from the center of the Earth), +z out of the page toward you), what

is the vector gravitational force on a 31 kg object sitting on the ground? (From the momentum principle you can conclude that a force of the same magnitude is exerted upward by the ground on the object if the momentum isn't changing. In Chapter 4 we'll see more about the origin of this force.)
Physics
1 answer:
skad [1K]3 years ago
5 0

Answer:

The vector gravitational force is  W = 303.8\  N( -y)

Explanation:

From the question we are told that

      The mass of the object is  m  = 31 \ kg

      The acceleration due to gravity experienced by the object is g =  9.8 m/s^2

Generally the vector gravitational force on the object is mathematically represented as

                       W = 31 *  9.8

                       W = 303.8\  N (-y)

The  -y indicates that the direction of the force is towards the center of the earth

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(a) Calculate the height of a cliff if it takes 2. 35 s for a rock to hit the ground when it is thrown straight up from the clif
Natali [406]

(a) The height of the cliff will be 8.26 meters.

(b) The time would it take to reach the ground will be 0.717 sec.

<h3>What is velocity?</h3><h3 />

The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity. it is a time-based component.

(a) The height of the cliff will be 8.26 meters.

According to Newton's second equation of motion

\rm H =ut-\frac{1}{2} gt^2 \\\\ \rm H =8\times 2.35-\frac{1}{2} 9.81 (2.35)^2\\\\\rm H =8.16 \; m

Hence The height of the cliff will be 8.26 meters.

(b)The time would it take to reach the ground will be 0.717 sec.

We must have the final velocity to find the time so;

\rm v^2=u^2+2gh\\\\ \rm v^2=8^2+2\times 9.81 \times 8.6 \\\\ \rm v= \sqrt{8^2+2\times 9.81 \times 8.6}\\\\\rm v=15.03 \;m/sec

According to Newton's third equation of motion ;

\rm v=u-gt \\\\ \rm t=\frac{v-u}{g} \\\\ \rm t=\frac{15.03-8}{9.81} \\\\ \rm t=0.717 sec.

Hence the time would it take to reach the ground will be 0.717 sec.

To learn more about the velocity refer to the link ;

brainly.com/question/862972

3 0
2 years ago
Which of the following is not an example of kinetic energy being converted to potential energy?
KengaRu [80]

The list of choices you provided with your question
is utterly devoid of any such examples.

6 0
3 years ago
Read 2 more answers
State the difference between sensible heat and latent heat
Anna11 [10]

<u>Latent hea</u>t is related to changes in phase between liquids ,gases and solids.

<u>Sensible heat</u> is related to changes in temperature of a gas or object with no change in phase.

6 0
3 years ago
An automobile rounds a curve of radius 50.0 m on a flat road.
bixtya [17]

Answer:

14m/s

Explanation:

Given parameters:

Radius of the curve  = 50m

Centripetal acceleration  = 3.92m/s²

Unknown:

Speed needed to keep the car on the curve = ?

Solution:

The centripetal acceleration is the inwardly directly acceleration needed to keep a body along a curved path.

 It is given as;

      a = \frac{v^{2} }{r}  

a is the centripetal acceleration

v is the speed

r is the radius

  Now insert the parameters and find v;

         v²   = ar

        v² = 3.92 x 50  = 196

         v  = √196 = 14m/s

6 0
3 years ago
13
gladu [14]

v = u + at

50 = 0 + a*10

50 = 10a

a = 5 m/s^2

4 0
2 years ago
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