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3 years ago

9

Which part of a feedback mechanism causes change to make up for the departure from the set point? A. sensor B. effector C. respo

nse D. integrating center

1 answer:

klemol [59]3 years ago

6 0

B.) Effector
I believe so lol

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A chemist wants to use an element with a large electronegativity for an experiment. Based on trends in the periodic table, which

Sidana [21]

Answer:

Halogens

Explanation:

Electronegativity increases from <em>left to right</em> in the Periodic Table (see image).

We ignore the elements of Group 18 (the noble gases) because they are quite unreactive.

So, the most electronegative elements are those in Group 17 (the <em>halogens</em>).

6 0

3 years ago

Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0

klemol [59]

Answer:

Partial pressure of methane: 1.18 atm

Partial pressure of ethane: 1.45 atm

Partial pressure of propane: 2.35 atm

Explanation:

Let the total moles of gases in a container be n.

Total pressure of the gases in a container =P = 5.0 atm

Temperature of the gases in a container =T = 23°C = 296.15 K

Volume of the container = V = 10.0 L

$PV=nRT$ (Ideal gas equation)

$n=\frac{PV}{RT}=\frac{5.0 atm\times 10.0 L}{0.0821 atm L/mol K\times 296.15 K}=2.0564 mol$

Moles of methane gas = $n_1=\frac{8.00 g}{16.04 g/mol}=0.4878 mol$

Moles of ethane gas = $n_2=\frac{18.00 g}{30.07 g/mol}=0.5986 mol$

Moles of propane gas = $n_3=?$

$n=n_1+n_2+n_3$

$n_3=n-n_1-n_2=2.0564 mol-0.4878 mol-0.5986 mol= 0.9700 mol$

Partial pressure of all the gases can be calculated by using Raoult's law:

$p_i=P\times \chi_i$

$p_i$ = partial pressure of 'i' component.

$\chi_1$ = mole fraction of 'i' component in mixture

P = total pressure of the mixture

Partial pressure of methane:

$p_1=P\times \chi_1=P\times \frac{n_1}{n_1+n+2+n_3}=P\times \frac{n_1}{n}$

$p_1=5.00 atm\times \frac{0.4878 mol}{2.0564 mol}=1.18 atm$

Partial pressure of ethane:

$p_2=P\times \chi_2=P\times \frac{n_2}{n_1+n+2+n_3}=P\times \frac{n_2}{n}$

$p_2=5.00 atm\times \frac{0.5986 mol}{2.0564 mol}=1.45 atm$

Partial pressure of propane:

$p_3=P\times \chi_3=P\times \frac{n_3}{n_1+n+2+n_3}=P\times \frac{n_3}{n}$

$p_3=5.00 atm\times \frac{0.9700 mol}{2.0564 mol}=2.35 atm$

5 0

3 years ago

How much heat energy is needed to raise the temperature of 59.7g of cadmium from 25°C to 100°C? The specific heat of cadmium is

labwork [276]

Using the Fundamental Equation of Calorimetry, we have:

$Q=mc\Delta T \\ Q=59.7.0.231.(100-25) \\ \boxed {Q=1034.3025J}$

If you notice any mistake with my english, please know me, because I am not native.

7 0

3 years ago

What would you need to do to calculate the molality of 10 mol of NaCl in 200

Makovka662 [10]

It will be the second one

8 0

3 years ago

What depends on public opinion and support? A. regulations at a local level B. enforcement of laws C. success of a policy D. rev

Nastasia [14]

i believe the answer is success of a policy. if this was correct please mark brainliest and lmk if you have any more questions x

3 0

3 years ago