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3 years ago

A 10 kg animal is running at a rate of 3.0 m/s. What is the kinetic energy of the animal?

Physics

1 answer:

emmasim [6.3K]3 years ago

8 0

Answer:

The kinetic energy of the animal is 45 Joule.

Explanation:

Kinetic energy of the animal is given by,

Kinetic energy = $\frac{1}{2} m v^{2}$

Given: m = 10 kg , v = 3 m/s

Thus,

Kinetic energy = $\frac{1}{2} (10) (3)^{2}$

Kinetic energy = 45 Joule,

The kinetic energy of the animal is 45 Joule.

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$\sf \large y = v_{yi} \times t - (\frac{1}{2} \times g \times {t}^{2}) \\ \\ \sf \large y = v_i \times \cos \theta \times t - \frac{1}{2} g {t}^{2}$

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$\textsf{ \large {\underline{Now substituting the required values}} }$

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$\sf y = 100 \times \cos55{ \degree} \times 12 - \frac{1}{2} \times 9.80 \times {12}^{2} \\ \\ \sf y = 100 \times 0.8192 \times 12 - 0.5 \times 9.8 \times 144 \\ \\ \sf y = 983.04 - 705.6 \\ \\ \underline{ \boxed{ \bold{y = 277.44m}}}$

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<h3>Henceforth, the distance at horizon is 688.32m and at vertical is 277.44m.</h3>

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