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GrogVix [38]
3 years ago
11

Which of the following statements accurately describes the expression x+5/x^2-2

Mathematics
2 answers:
Mazyrski [523]3 years ago
6 0

Answer:

the quotient of x+5 and x^2-2

Step-by-step explanation:


AlexFokin [52]3 years ago
4 0
What are the statements that you have that are to describe the expression?
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Can someone please help me find the area?
rewona [7]

Answer:

90+20=110 square cm

Step-by-step explanation

(10*(14-5)+(5*(10-6)

=90+20

=110

4 0
3 years ago
Read 2 more answers
I need answers for 1 and 2
Snowcat [4.5K]

1. Slope 3/4, through (4,-1)

y = 3/4 x + b

-1 = 3/4(4) + b

-1 = 3 + b

-1 - 3 = b

-4 = b

y = 3/4 x - 4

2. Slope = - 1/2, through (3,0)

y = -1/2 x + b

0 = -1/2(3) + b

0 = -1.5 + b

0 + 1.5 = b

1.5 = b

y = -1/2 x + 1.5

8 0
2 years ago
Each lap around the track is 400 meters. How many meters does someone run if they runs if Noah ran 14 laps, how many meters did
sashaice [31]
Question 1: You just do 400 x 14, and the answer is 5,600.
Question 2: You divide 7,600 by 400, and the answer is 19.
7 0
2 years ago
Read 2 more answers
1) 28 + 3[{12 + 2 (14~4) = 5} - 6] 3​
nasty-shy [4]

Answer:

Step-by-step explanation:

whats ur question?

8 0
2 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
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