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Mamont248 [21]
3 years ago
5

Which of the following describes the relationship correctly?

Chemistry
2 answers:
galben [10]3 years ago
8 0
A. Air expands, becomes less dense and rises when the temperature is high due to the increased kinetic energy. This causes the air molecules to move around much more so they are further apart.
SOVA2 [1]3 years ago
8 0

Answer: Option (A) is the correct answer.

Explanation:

Density is defined as the degree of compactness or mass per unit volume of a substance.

When air expands then it means its molecules have gained kinetic energy. Therefore, they are colliding with each other and result in expansion of air.

So, expansion makes air less dense as mass per unit volume decreases on expansion. Therefore, air rises on expansion.

Thus, we can conclude that air expands, becomes less dense, and rises describes the relationship correctly.

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The half-life of a strontium isotope is 25 years. How much of this particular isotope will remain after 100 years if the startin
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Answer:

1 gram

Explanation:

Half life = 25 years

Starting mass = 16 grams

Time = 100 years

Number of half lives = Time / Duration of Half life = 100 / 25 = 4

After first Half life;

Remaining mass = 16 / 2 =  8 g

After Second Half life;

Remaining mass = 8 / 2 =  4 g

After Third Half life;

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After Fourth Half life;

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Explain the reaction between metallic hydroxides and a dilute acid?
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The hydroxide (OH) in the metallic hydroxide will react with the hydrogen in an acid to form H2O. The remaining ions will combine to form a salt. Therefore a metal hydroxide and an acid will form a salt + water.
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1. Show the mechanism for the main product for the monochlorination of 2-methylbutane. List all other products.
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Answer:

See explanation below

Explanation:

First, we need to understand that the monochlorination of an alkane like this one, involves substitution of one of the atoms of hydrogen of the molecule for an atom of chlorine.

This reaction takes place when the alkane reacts with Cl₂ in presence of light or heat.

When this happens, the first step involves the breaking of the double bond of the chlorine to form the ion Cl⁻.

The next step involves the substraction of the hydrogen of the molecule by the Chlorine. This will leave the alkane with a lone pair available for reaction.

The third step, the alkane with the lone pair of electron substract a chlorine for the beggining and form the mono chlorinated product.

The final step involves forming the remaining products with the remaining reagents there.

In the picture attached you have the mechanism and product for this reaction:

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