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Varvara68 [4.7K]
2 years ago
10

Calculate the height of a cliff if it takes 2.35s for a rock to hit the ground when it is thrown straight up from the cliff with

a initial velocity 8m/s.​
Physics
1 answer:
ad-work [718]2 years ago
7 0

Answer:

y₀ = 10.625 m

Explanation:

For this exercise we will use the kinematic relations, where the upward direction is positive.

         y = y₀ + v₀ t - ½ g t²

in the exercise they indicate the initial velocity v₀ = 8 m / s.

when the rock reaches the ground its height is zero

         0 = y₀ + v₀ t - ½ g t²

        y₀i = -v₀ t + ½ g t²

let's calculate

         y₀ = - 8  2.5 + ½  9.8  2.5²

         y₀ = 10.625 m

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leonid [27]

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Explanation:

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3 0
3 years ago
An object moving with a speed of 35 m/a and has a kinetic energy of 1500j, what is the mass of the object
EleoNora [17]

Explanation:

Speed or velocity (V) = 35 m/s

Kinetic energy (K. E) = 1500 Joule

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We know

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m = 3000 / 1225

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The mass of the object is 2.45 kg

Hope it will help :)

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3 years ago
If the angular velocity of the pully is -8.4rad/s at a given time, and its anglar acceleration is -2.8rad/s2, what is the angula
snow_lady [41]

Here we know that

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\alpha = - 2.8 rad/s^2

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now from kinematics we have

\omega_f = \omega_i + \alpha t

now from above all values we have

\omega_f = (-8.4 rad/s) + (-2.8 rad/s^2)(1.5)

\omega_f = -8.4 + (-4.2)

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6 0
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If a circuit has a power of 50 W with a current of 4.5 A, what is the resistance in the circuit?
lawyer [7]

Answer:

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At what rate is soda being sucked out of a cylindrical glass that is 6 in tall and has radius of 2 in? The depth of the soda dec
evablogger [386]

Answer:

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