How many moles are in 73.4 grams of Phosphorus?

Convert 543 g to kg (Use correct number of significant figures for answer).

andrew11 [14]

Answer:

0.543 kilogram

Explanation:

thats the answer

5 0

3 years ago

A pool ball moving 1.33 m/s strikes an identical ball at rest. Afterward, the first ball moves 0.750 m/s at a 33.30 angle. What

kramer

Explanation:

We need to apply the conservation law of linear momentum to two dimensions:

Let $p_{1}$ = momentum of the 1st ball

$p_{2}$ = momentum of the 2nd ball

In the x-axis, the conservation law can be written as

$(p_{1} \cos \theta_{1})_{i} + (p_{2} \cos \theta_{2})_{i} = (p_{1} \cos \theta_{1})_{f} + (p_{2} \cos \theta_{2})_{f}$

or

$(m_{1}v_{1})_{i}= (m_{1}v_{1}\cos \theta_{1})_{f} + (m_{2}v_{2}\cos \theta_{2})_{f}$

Since we are dealing with identical balls, all the m terms cancel out so we are left with

$(v_{1})_{i} = (v_{1})_{f}\cos \theta_{1} + (v_{2})_{f}\cos \theta_{2}$

Putting in the numbers, we get

$1.33 = (0.750) \cos(33.30) + (v_{2})_{f} \cos \theta_{2}$

$= > (v_{2})_{f} \cos \theta_{2} = 0.703$

In the y-axis, there is no initial y-component of the momentum before the collision so we can write

$0 = (v_{1}\sin \theta_{1})_{f} + (v_{2}\sin \theta_{2})_{f}$

or

$= > (v_{2})_{f} \sin \theta_{2} = (0.750) \sin(33.30) = 0.412$

Taking the ratio of the sine equation to the cosine equation, we get

$\frac{ \sin \theta _{2}}{ \cos \theta_{2} } = \tan \theta_{2} = \frac{0.412}{0.703} = 0.586$

or

$\theta_{2} = { \tan}^{ - 1} (0.586) = 30.4$

Solving now for $(v_{2})_{f}$ ,

$(v_{2})_{f} = \frac{0.412}{ \sin(30.4) } = 0.815 \: \frac{m}{s}$

3 0

3 years ago

-A city and an international airport are 46 km away from each other. A maglev train takes 11

Wittaler [7]

Answer:

Explanation:

Given the following data;

Distance = 46 km

Time = 11 minutes

To find the average speed;

Speed = distance/time

7 0

2 years ago

The law of interia applies to objects

Yakvenalex [24]

Are there options to this question?

8 0

3 years ago

1. Sketch graphs of the momenta of asteroids A and B before the collision.

taurus [48]

<span>First, there is no external force acting on the asteroids ( I don't think so, since they are travelling at constant velocity). Since there is no external force acting on the individual asteroids, their respective momenta are constant in time as well. So, in your momentum v/s Time graph, the momenta for each asteroid will correspond to a straight line parallel to time axis. This happens until they collide. On collision an impulse acts on each asteroid ( by Newton's third law, the same magnitude of impulse acts on the two bodies). Due to this impulse, their respective momenta will change. You just need a little mathematics to figure out the respective momenta after the collision. Keep in mind there is no external force on the system, so after collision, the asteroids would again move with constant velocities. (Conservation of linear momentum of the system would help! You just need another equation to find out the velocities)</span>

8 0

3 years ago

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