The density of pure gold (au) is 19.3 g/cm3. what is the mass of a block of gold that measures 1.2 cm x 5.00 cm x 3.20 cm? please show work.
Given: Density of pure gold = 19.3 g /cm^3
Measurement of block of gold =1.2 cm x 5.00 cm x 3.20 cm
To calculate : mass of gold
Formula used: Density = Mass / Volume
Volume = 1.2 cm x 5.00 cm x 3.20 cm = 19.2 cm^3
Mass of gold = Density X volume = 19.3 g /cm^3 X 19.2 cm^3 = 370.56 g
Explanation:
Relation between length of a curve and angle is as follows.
l = 
where, R = radius of curve
= angle in radians
Also, l = 
.......... (1)
If curve has a degree of curvature 
for standard length s, then
R = 
........... (2)
Now, substitute the value of R from equation (2) into equation (1) as follows.
l = 
If s = 30 m, then calculate the value of l as follows.
l =
= 
= 452 m
thus, we can conclude that the length of the curve is 452 m.
Answer:
19. Option B. ⁰₋₁B
20. Option D. ²¹⁰₈₄Po
Explanation:
19. ²²⁸₈₈Ra —> ²²⁸₈₉Ac + ʸₓZ
Thus, we can determine ʸₓZ as follow:
228 = 228 + y
Collect like terms
228 – 228 = y
y = 0
88 = 89 + x
Collect like terms
88 – 89 = x
x = –1
Thus,
ʸ ₓZ => ⁰₋₁Z => ⁰₋₁B
²²⁸₈₈Ra —> ²²⁸₈₉Ac + ʸₓZ
²²⁸₈₈Ra —> ²²⁸₈₉Ac + ⁰₋₁B
20. ᵘᵥX —> ²⁰⁶₈₂Pb + ⁴₂He
Thus, we can determine ᵘᵥX as follow:
u = 206 + 4
u = 210
v = 82 + 2
v = 84
Thus,
ᵘᵥX => ²¹⁰₈₄X => ²¹⁰₈₄Po
ᵘᵥX —> ²⁰⁶₈₂Pb + ⁴₂He
²¹⁰₈₄Po —> ²⁰⁶₈₂Pb + ⁴₂He
I believe the answer is sugarcane
Answer:
yes, in certain cases
there are different types of bondings between atoms
and in some they lend electrons to make their atom stable this type of bonding is called ionic bonding
and in covalent bond the atoms share their electrons
