1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexeev081 [22]
3 years ago
6

A 1400 kg wrecking ball hangs from a 20-m-long cable. the ball is pulled back until the cable makes an angle of 30.0 ∘ with the

vertical.part aby how much has the gravitational potential energy of the ball changed?

Physics
2 answers:
anastassius [24]3 years ago
5 0

From the geometry of the problem, the 20 m-long cable creates the hypotenuse of a right triangle, with the extended of the other two sides of size 20 m * cos(30 deg), which is around 17.3 m. Therefore, the ball has increased by 20 m - 17.3 m = 2.7 m. 

The potential energy will have altered by m*g*h, which is 1400 kg * 9.8 m/s^2 * 1.6 m , or about 37044 joules.

Bas_tet [7]3 years ago
3 0

The gravitational potential energy of the ball changes by about

37000 J

\texttt{ }

<h3>Further explanation</h3>

Let's recall the formula of Gravitational Potential Energy as follows:

\large {\boxed {E_p = mgh }

<em>Ep = Gravitational Potential Energy ( Newton )</em>

<em>m = Object's Mass ( kg )</em>

<em>g = Gravitational Acceleration ( m )</em>

<em>h = Height ( m )</em>

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of wrecking ball = m = 1400 kg

length of the cable = L = 20 m

angle with the vertical = θ = 30.0°

<u>Asked:</u>

gravitational potential energy = Ep = ?

<u>Solution:</u>

Ep = m g h

Ep = m g (L - L\cos \theta)

Ep = 1400 ( 9.8 ) ( 20 - 20 \cos 30^o )

Ep = 13720 ( 20 - 10\sqrt{3} )

Ep \approx 37000 \texttt{ J}

\texttt{ }

<h3>Conclusion:</h3>

The gravitational potential energy of the ball changes by about

37000 J

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

You might be interested in
In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The co
labwork [276]

Answer:

The answer is given below

Explanation:

u is the initial velocity, v is the final velocity. Given that:

m_1=0.6kg,u_1=-5m/s(moving \ west),m_2=0.8kg,u_2=2m/s,k=1200N/m

a)

The final velocity of cart 1 after collision is given as:

v_1=(\frac{m_1-m_2}{m_1+m_2})u_1+\frac{2m_2}{m_1+m_2}u_2\\  Substituting:\\v_1=\frac{0.6-0.8}{0.6+0.8} (-5)+\frac{2*0.8}{0.6+0.8}(2)= 5/7+16/7=3\ m/s

The final velocity of cart 2 after collision is given as:

v_2=(\frac{m_2-m_1}{m_1+m_2})u_2+\frac{2m_1}{m_1+m_2}u_1\\  Substituting:\\v_1=\frac{0.8-0.6}{0.6+0.8} (2)+\frac{2*0.6}{0.6+0.8}(-5)= 2/7-30/7=-4\ m/s

b) Using the law of conservation of energy:

\frac{1}{2}m_1u_1+ \frac{1}{2}m_2u_2=\frac{1}{2}m_1v_1+\frac{1}{2}m_2v_2+\frac{1}{2}kx^2\\x=\sqrt{\frac{m_1u_1+m_2u_2-m_1v_1-m_2v_2}{k}}\\ Substituting\ gives:\\x=\sqrt{\frac{0.6*(-5)^2+0.8*2^2-(0.6*3^2)-(0.8*(-4)^2)}{1200}}=\sqrt{0}=0\ cm

7 0
3 years ago
Explain why electric forces are essential to forming compounds
Nina [5.8K]
It <span>Ions were once atoms with the same number of electrons and protons. Since they have opposite charges atoms are neutral. When they become ions the lose or gain electrons and become unbalanced. ... These different charges are attracted to each other via electric forces.</span>
7 0
3 years ago
Is
ivann1987 [24]

Answer:

Required energy Q = 231 J

Explanation:

Given:

Specific heat of copper C = 0.385 J/g°C

Mass m = 20 g

ΔT = (50 - 20)°C = 30 °C

Find:

Required energy

Computation:

Q = mCΔT

Q = 20(0.385)(30)

Required energy Q = 231 J

4 0
2 years ago
A business letter is informal correspondence and is sent to people within
jarptica [38.1K]

Answer:

FALSE!!!

Explanation:

Business letters are formal and normally given to someone of higher importance.

5 0
3 years ago
PLEASE HELP!!!! The displacement vectors A and B, when added together, give the resultant vector R, so that R = A + B. Use the d
GuDViN [60]

Answer:

Ax = 0

Ay = 6 m

Bx = 8 cos phi = cos 34 = 6.63 m

By = 8 sin phi = 8 sin (-34) = -4.47 m

Rx = Ax + Bx = 0 + 6.63 = 6.63 m

Ry = Ay + By = 6 - 4.47 = 1.53 m

R = (6.63^2 + 1.53^2)^1/2 = 6.80 m

tan theta = Ry / Rx = 1.53 / 6.8 = ,225

theta = 12.7 deg

7 0
3 years ago
Other questions:
  • Help me please. I’ll select brainliest!
    8·2 answers
  • Which of the following changes occurs naturally in a system over time?
    14·1 answer
  • P and s waves from an earthquake travel at different speeds, and this difference helps in locating the earthquake âepicenterâ (w
    14·1 answer
  • What does that make?
    12·2 answers
  • What determines how the different moon phases appear from earth
    14·2 answers
  • The two cars collide at right angles in the intersection of two icy roads. Car A has a mass of 1965 kg and car B has a mass of 1
    13·1 answer
  • Which provides the best analogy for an electron in an atomic orbital?
    14·1 answer
  • 7. Un niño tiene 35 kg esta sobre un trineo que tiene una masa de 5 kg. Si el niño y el trineo
    8·1 answer
  • Which equation is used to find an object's acceleration?
    9·1 answer
  • Can somebody pls pls help
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!