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Alexeev081 [22]
4 years ago
6

A 1400 kg wrecking ball hangs from a 20-m-long cable. the ball is pulled back until the cable makes an angle of 30.0 ∘ with the

vertical.part aby how much has the gravitational potential energy of the ball changed?

Physics
2 answers:
anastassius [24]4 years ago
5 0

From the geometry of the problem, the 20 m-long cable creates the hypotenuse of a right triangle, with the extended of the other two sides of size 20 m * cos(30 deg), which is around 17.3 m. Therefore, the ball has increased by 20 m - 17.3 m = 2.7 m. 

The potential energy will have altered by m*g*h, which is 1400 kg * 9.8 m/s^2 * 1.6 m , or about 37044 joules.

Bas_tet [7]4 years ago
3 0

The gravitational potential energy of the ball changes by about

37000 J

\texttt{ }

<h3>Further explanation</h3>

Let's recall the formula of Gravitational Potential Energy as follows:

\large {\boxed {E_p = mgh }

<em>Ep = Gravitational Potential Energy ( Newton )</em>

<em>m = Object's Mass ( kg )</em>

<em>g = Gravitational Acceleration ( m )</em>

<em>h = Height ( m )</em>

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of wrecking ball = m = 1400 kg

length of the cable = L = 20 m

angle with the vertical = θ = 30.0°

<u>Asked:</u>

gravitational potential energy = Ep = ?

<u>Solution:</u>

Ep = m g h

Ep = m g (L - L\cos \theta)

Ep = 1400 ( 9.8 ) ( 20 - 20 \cos 30^o )

Ep = 13720 ( 20 - 10\sqrt{3} )

Ep \approx 37000 \texttt{ J}

\texttt{ }

<h3>Conclusion:</h3>

The gravitational potential energy of the ball changes by about

37000 J

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

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Let the center of mass is at x distance from the canoe center and it will be towards the Ricardo cause. So the toque around the center of mass is given as

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Substitute in the above equation we get

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Fill in the blanks for the following:
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where M is the molar mass of oxygen gas = 31.9 g/mol = 0.0319 kg/mol

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\frac{Voxy}{Vnit} = \sqrt{\frac{Mnit}{Moxy} }

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