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Alexeev081 [22]
3 years ago
6

A 1400 kg wrecking ball hangs from a 20-m-long cable. the ball is pulled back until the cable makes an angle of 30.0 ∘ with the

vertical.part aby how much has the gravitational potential energy of the ball changed?

Physics
2 answers:
anastassius [24]3 years ago
5 0

From the geometry of the problem, the 20 m-long cable creates the hypotenuse of a right triangle, with the extended of the other two sides of size 20 m * cos(30 deg), which is around 17.3 m. Therefore, the ball has increased by 20 m - 17.3 m = 2.7 m. 

The potential energy will have altered by m*g*h, which is 1400 kg * 9.8 m/s^2 * 1.6 m , or about 37044 joules.

Bas_tet [7]3 years ago
3 0

The gravitational potential energy of the ball changes by about

37000 J

\texttt{ }

<h3>Further explanation</h3>

Let's recall the formula of Gravitational Potential Energy as follows:

\large {\boxed {E_p = mgh }

<em>Ep = Gravitational Potential Energy ( Newton )</em>

<em>m = Object's Mass ( kg )</em>

<em>g = Gravitational Acceleration ( m )</em>

<em>h = Height ( m )</em>

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of wrecking ball = m = 1400 kg

length of the cable = L = 20 m

angle with the vertical = θ = 30.0°

<u>Asked:</u>

gravitational potential energy = Ep = ?

<u>Solution:</u>

Ep = m g h

Ep = m g (L - L\cos \theta)

Ep = 1400 ( 9.8 ) ( 20 - 20 \cos 30^o )

Ep = 13720 ( 20 - 10\sqrt{3} )

Ep \approx 37000 \texttt{ J}

\texttt{ }

<h3>Conclusion:</h3>

The gravitational potential energy of the ball changes by about

37000 J

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

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Complete Question

A power supply has an open-circuit voltage of 40.0 V and an internal resistance of 2.00 \Omega. It is used to charge two storage batteries connected in series, each having an emf of 6.00 V and internal resistance of 0.300\Omega . If the charging current is to be 4.00 A, (a) what additional resistance should be added in series? At what rate does the internal energy increase in (b) the supply, (c) in the batteries, and (d) in the added series resistance? (e) At what rate does the chemical energy increase in the batteries?

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Explanation:

From the question we are told that

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