Answer:
a) q_1=q_2= 7.42*10^-7 C
b) q_2= 3.7102*10^-7 C , q_1 = 14.8*10^-7 C
Explanation:
Given:
F_e = 0.220 N
separation between spheres r = 0.15 m
Electrostatic constant k = 8.99*10^9
Find: charge on each sphere
part a
q_1 = q_2
Using coulomb's law:
F_e = k*q_1*q_2 / r^2
q_1^2 = F_e*r^2/k
q_1=q_2= sqrt (F_e*r^2/k)
Plug in the values and evaluate:
q_1=q_2= sqrt (0.22*0.15^2/8.99*10^9)
q_1=q_2= 7.42*10^-7 C
part b
q_1 = 4*q_2
Using coulomb's law:
F_e = k*q_1*q_2 / r^2
q_2^2 = F_e*r^2/4*k
q_2= sqrt (F_e*r^2/4*k)
Plug in the values and evaluate:
q_2= sqrt (0.22*0.15^2/4*8.99*10^9)
q_2= 3.7102*10^-7 C
q_1 = 14.8*10^-7 C
Natural gas is the answer.
There are four factors affecting resistance which are Temperature, Length of wire, Area of the cross-section of wire and nature of the material. When there is current in a conductive material, the free electrons move through the material and occasionally collide with atoms.
Answer:
mass: The quantity of matter which a body contains, irrespective of its bulk or volume. It is one of four fundamental properties of matter. It is measured in kilograms in the SI system of measurement.
Explanation:
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Answer:
Explanation:
Well you have the voltages right, and that is no trivial matter. Each one of the resistors in a parallel circuit sees the same input voltages (in this case 6).
Now I think it would be a good idea to fill in the the resistance column.
R1 = 3 ohms
R2 = 6 ohms
R3 = 2 ohms
The total resistance can be calculated in two ways. I'll get around to doing both of them but I'll do the conventional way first. One hint: the total resistance must be smaller than the smallest resistor. Read that sentence over a couple of times. What it means is that it must be less than 2 ohms in a parallel circuit.
1/r1 + 1/r2 + 1/r3 = 1/rt
1/3 + 1/6 + 1/2 = 1/rt
Change all the denominators to 6ths.
2/6 + 1/6 + 3/6 = 1/rt
(2 + 1 + 3)/6 = 6/6 = 1
rt = 1
====================
So the current I is V/R
V = 6
R = 1
Current = V/R = 6/1 = 6 amps.
====================
The current in each resistor is
I1 = V / R1
I1 = 6/3 = 2 amps
I2 = V/R2
I2 = 6/6 = 1 amp
I3 = 6/2 = 3 amps
The total is I1 + I2 + I3 = 2 + 1 + 3 = 6 amps.
======================
Remember I said there was 2 ways of figuring out the total resistance. I did one of them about. Here's the other.
R = V / It
R = 6 / 6
R = 1 ohm just what you got before.
====================
Power
P = V * I
P1 = 6 * 2 = 12 watts
P2 = 6*1 = 6 watts
P3 = 6*3 = 18 watts
Pt = 36 watts.
Pt can be done by using the voltage * the total current
Pt = 6 volts * 6 amps = 36 watts, just what you would expect.
