Answer: a) 1875m. (b) 8.66s
Explanation:
9) Cart 1 has a mass of 4 kg and an initial speed of 4 m/s. It eventually elastically collides with cart 2, whose mass is 6 kg,
and which moves at an initial speed of 4 m/s toward cart 1. How fast are the carts moving after their collision? [Enter cart 1's final speed in answer box 1 and cart 2's final speed in answer box 2.]
1 answer:
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Answer:20.03 m/s
Explanation:
Given
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Answer:
Explanation:
P = Power Output = 1000 W
r = Radius = 35000000 m
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c = Speed of light =
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The minimum speed with which a projectile will travel a range is given by the speed when the given range is taken as the maximum range for the given speed
The minimum takeoff speed for such a leap is approximately 9.9 m/s
The known parameter is the distance a grey kangaroo can leap = 10 meters
The required information is the minimum takeoff speed for the leap
Solution:
The path of motion of the kangaroo as they leap is the path of a projectile
The distance of the leap is the range of the projectile
The formula for the maximum range is presented as follows;
v₀ = The initial speed of the kangaroo
g = The acceleration due to gravity ≈ 9.81 m/s²
The minimum speed to reach a maximum range of, R = 10 meters is found as follows;
Therefore;
v₀² = 10 m × 9.81 m/s² = 98.1 m²/s²
v₀ = √(98.1 m²/s²) ≈ 9.9 m/s
The minimum takeoff speed for the kangaroo to leap 10 meters on horizontal ground, v₀ ≈ 9.9 m/s
Learn more about projectile motion here: