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vesna_86 [32]
3 years ago
9

9) Cart 1 has a mass of 4 kg and an initial speed of 4 m/s. It eventually elastically collides with cart 2, whose mass is 6 kg,

and which moves at an initial speed of 4 m/s toward cart 1. How fast are the carts moving after their collision? [Enter cart 1's final speed in answer box 1 and cart 2's final speed in answer box 2.]

Physics
1 answer:
postnew [5]3 years ago
3 0

Answer:

Cart 1 = 4 m/s

Cart 2 = 4 m/s

Explanation:

See attachment

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Calculati rezistenta filamentului unui bec al lanternei de buzunar daca la tensiunea de 3,5 v el este parcurs de un curent cu in
Gennadij [26K]

Answer:

Resistencia = 12.5 Ohmios

Explanation:

Dados los siguientes parámetros;

Voltaje = 3.5 Volts

Corriente = 0.28 Amps

Para encontrar el resistencia;

La ley de Ohm establece que a temperatura constante, la corriente que fluye en un circuito eléctrico es directamente proporcional al voltaje aplicado en los dos puntos e inversamente proporcional a la resistencia en el circuito eléctrico.

Matemáticamente, La ley de Ohm viene dada por la fórmula;

Voltaje = corriente * resistencia

Resistencia = voltaje/corriente

Resistencia = 3.5/0.28

Resistencia = 12.5 Ohmios

Por tanto, la resistencia del filamento de una linterna de bolsillo es de 12,5 ohmios.

3 0
3 years ago
Why are large astronomical bodies round
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<span>Matter of all types have gravity, which causes it to attract to each other. The most efficient way for all this matter to congregate is the sphere. As they consolidate, they form the shape. As they compress, temperatures in the center of the mass start to go up and if it hits the proper point, it can ignite and become a star.</span>
7 0
4 years ago
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In a thundercloud there may be an electric charge of 41 C near the top of the cloud and −41 C near the bottom of the cloud. If t
Andre45 [30]

Answer:

F = 236063.6N

Explanation:

Please see attachment below.

4 0
3 years ago
The magnetic field at the center of a 1.40-cm-diameter loop is 2.50 mT . PART A) What is the current in the loop?
NISA [10]

Explanation:

It is given that,

Diameter of loop, d = 1.4 cm

Radius of loop, r = 0.7 cm = 0.007 m

Magnetic field, B=2.5\ mT=2.5\times 10^{-3}\ T

(A) Magnetic field of a current loop is given by :

B=\dfrac{\mu_oI}{2r}

I is the current in the loop

I=\dfrac{2Br}{\mu_o}

I=\dfrac{2\times 2.5\times 10^{-3}\times 0.007}{4\pi \times 10^{-7}}

I = 27.85 A

(B) Magnetic field at a distance r from a wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

r=\dfrac{\mu_o I}{2\pi B}

r=\dfrac{4\pi \times 10^{-7}\times 27.85}{2\pi \times 2.5\times 10^{-3}}

r = 0.00222 m

r=2.2\times 10^{-3}\ m

Hence, this is the required solution.

3 0
3 years ago
when a tuning fork vibrates over an open pipe and the air in the pipe starts to vibrate, the vibrations in the tube are caused b
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Sound waves....................................
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4 years ago
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