Use this formula for an object starting from rest and accelerating:
Distance = (1/2) (acceleration) (time)²
In this problem, the distance is 40 meters, and acceleration is gravity.
So . . .
40 m = (1/2) (9.8 m/s²) (time)²
Divide each side by (4.9 m/s²) :
time² = (40 m) / (4.9 m/s²)
time² = 8.16 sec²
Take the square root of each side :
√(time²) = √(8.16 sec²)
time = 2.86 seconds
Round it to 2.9 sec <em>(choice B)</em>
Reflection occurs in many scenarios in our everyday life. Reflection occurs
when light travels in one medium and comes into contact with another.
However, what if a light wave is moving from one location to another but
the mediums stay the same, what happens to that light wave?*
it will reflect with the same amount of intensity
The answer is c Ai3n3 yea that’s the right answer idk
Answer:
Therefore the terminal velocity = 1.45 m/s
Explanation:
Terminal velocity: Terminal velocity is the highest velocity of an object when it falls from rest trough a media.
= terminal velocity
w = weight of the object = mg
= drag coefficient=0.80
A= frontal area
= media density = 1.2 kg/m³
m = mass = 8 kg
g= acceleration due to gravity = 9.8 m/s²
Front area = length× breadth
= (18×47)cm²
=846 cm²
Therefore the terminal velocity
=1.45 m/s
Therefore the terminal velocity = 1.45 m/s
Answer:
Im not sure if you mean miles per hour or meters per hour but if it is miles it is 4.97 miles per hour and if it is meters then it is 8000 meters per hour
Explanation:
Sorry if I'm wrong
