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Nikitich [7]
4 years ago
5

Two rocks weighing 5 Newtons and 10 Newtons are dropped simultaneously from the same height onto a Coyote. After three seconds o

f free fall (neglecting air resistance), compared to the 5 N rock, the 10 N rock has greater
Physics
1 answer:
Ilia_Sergeevich [38]4 years ago
5 0

<h2>Potential energy lost by 10 N rock will be greater</h2>

Explanation:

Two rocks of 5N and 10N falls from the same height . Thus they will loose the potential energy.

The potential energy lost = mass x acceleration due to gravity x height

The potential energy lost by first 5 N rock = 5 h

Because weight of rock m g = 5 N

Similarly , the potential energy lost by 10 N Rock = 10 h

here weight of rock m g = 10 N

Thus comparing these two , the potential energy lost by 10 N rock is greater than that of 5 N rock .

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The new frequency of oscillation when the car bounces on its springs is 0.447 Hz

<h3>Frequency of oscillation of spring</h3>

The frequency of oscillation of the spring is given by f = (1/2π)√(k/m) where

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Now since k is constant, and f ∝ 1/√m.

So, we have f₂/f₁ = √(m₁/m₂) where

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So, making f₂ subject of the formula, we have

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Substituting the values of the variables into the equation, we have

f₂ = [√(m₁/m₂)]f₁

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f₂ = 1.0 Hz/√5

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Learn more about frequency of oscillation of spring here:

brainly.com/question/15318845

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The awnser is d

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