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gtnhenbr [62]
3 years ago
9

The planet Mars has two moons – Phobos and Deimos. Phobos has a mass of 10.8 × 1015 kilograms, and Deimos has a mass of 2.0 × 10

15 kilograms. How much greater is the mass of Phobos than the mass of Deimos?
A) 8.8 × 1015 kilograms
B) 8.8 × 1016 kilograms
C) 9.2 × 1014 kilograms
D) 9.2 × 1015 kilograms
Mathematics
2 answers:
olga nikolaevna [1]3 years ago
8 0
It should be A (8.8 x 1015 kilograms)
riadik2000 [5.3K]3 years ago
8 0

Answer:

The correct answer is A

Step-by-step explanation:

Since the difference in their masses is 10,800,000,000,000,000 - 2,000,000,000,000,000 = 8,800,000,000,000,000 kilograms, the mass of Phobos is 8.8 × 1015 kilograms more than the mass of Deimos.

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Dakota knows that EJ←→⊥CN←→ and CN←→∥KT←→ .
Lina20 [59]

Answer:

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Step-by-step explanation:

Nothing in the problem statement tells you anything about the directions of lines LK or QT, so you cannot conclude they are parallel. You only know that EV crosses CN and KT at right angles.

EJ ⊥ CN means m∠CJV = 90°, as all angles at the intersection of EJ and CN are 90°.

6 0
3 years ago
In 2005 Richard earned £22,000 per year.
Slav-nsk [51]
It’s 45%

Explanation = 31900-22000/22000 • 100 = 45%
6 0
3 years ago
How to order -14.4, -14, -14 1/5 from least to greatest
ElenaW [278]
Think of  thermometer the negative degrees are the coldest so are the lowest on the vertical column

first convert -14 1/5 to decimals  =  -14.2

so the order is 

-14.4 , -14 1/5 , -14.

8 0
3 years ago
What is the third quartile, Q3, of the following distribution?
GREYUIT [131]

Answer:

The third quartile is:

Q_3=29

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile Q_3

For a set of n data organized in the form:

x_1, x_2, x_3, ..., x_n

The third quartile is  Q_3:

Q_3=x_{\frac{3}{4}(n+1)}

With n=20

Q_3=x_{\frac{3}{4}(20+1)}

Q_3=x_{15.75}

The third quartile is between x_{15}=29 and x_{16}=29

Then

Q_3 =x_{15} + 0.75*(x_{16}- x_{15})

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5 0
3 years ago
Read 2 more answers
Find all solutions to the equation:
crimeas [40]

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That turns into 7z^2 - 14z + 7 = 0 after adding 5 to both sides. Use the quadratic formula to solve for z. The only solution is z = 1 (see attached image). Since we made z = sin(x), this means sin(x) = 1. All solutions to this equation will be in the form x = (pi/2) + 2pi*n, which is the radian form of the solution set. If you need the degree form, then it would be x = 90 + 360*n

The 2pi*n (or 360*n) part ensures we get every angle coterminal to pi/2 radians (90 degrees), which captures the entire solution set.

Note: The variable n can be any integer.

7 0
3 years ago
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