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2 years ago

6

Which of the following is not a component of a normal experiment?

1 answer:

MaRussiya [10]2 years ago

4 0

Answer:

D. Validity group

Explanation:

A validity group is not necessarily a component of a normal experiment.

A normal experiment is made up of the dependent variables, independent variables, and most times the control group.

The dependent variable is one that relies on the outcome of the effect produced from the experimental design
The independent variable is the one that causes a desired effect under the study.
The control group is a group that does not receive any treatment nor attenuation of the conditions.

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Find the hiker’s gravitational potential energy if the cliff is 60m high

Furkat [3]

Answer:

Potential energy is $U=mgh$

Explanation:

The potential energy depends on the mass, the acceleration of gravity g and the height at which the object or person is.

Potential energy $U=mgh$

In this case we would need to know the exact mass of the hiker in order to calculate the potential energy.

But we know the values of g and h

$g=9.81m/s^2$

$h=60m$

So, the potential energy

$U=m(9.81m/s^2)(60m)\\\\U=588.6*m$

m is the mass of the hiker, wich is not in the description of the problem.

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3 years ago

A motorcycle that is slowing down uniformly. The motorcycle covers 1 ????m=1000 m in 80 sec⁡. The motorcycle then covers the nex

Lynna [10]

Answer:

Part a)

acceleration = -0.042 m/s/s

Part b)

initial speed = 14.17 m/s

final speed = 5.77 m/s

Explanation:

Part a)

Let the initial velocity of the motorcycle is

$v_i = v_o$

now at the end of 80 s let the speed is

$v_f = v_1$

after another 120 s let the speed will be

$v_f' = v_2$

now we know that

$d = \frac{v_i + v_f}{2} (t)$

$d = \frac{v_o + v_1}{2}(80)$

$1000 = 40(v_o + v_1)$

also we know that

$v_1 - v_o = a(80)$

also we have

$1000 = \frac{v_1 + v_2}{2}(120)$

$1000 = 60(v_1 + v_2)$

now we can say

$(v_2 + v_1) - (v_o + v_1) = \frac{50}{3} - \frac{50}{2}$

also we know

$v_2 - v_o = a(120 + 80)$

$-8.33 = 200 a$

$a = -0.042 m/s^2$

Part b)

now we have

$v_1 + v_o = 25$

$v_1 - v_o = (-0.042)(80)$

$v_1 = 10.83 m/s$

so the starting velocity of the trip is

$v_o = 25 - 10.83 = 14.17 m/s$

now speed after t = 200 s is given as

$v_2 = v_o + at$

$v_2 = 14.17 - (0.042)(200)$

$v_2 = 5.77 m/s$

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3 years ago