Answer:
The flux of the electric field through the surface is 3.24\times10^{3}\ Nm^/C[/tex].
Explanation:
Given that,
Area of cube = 48 cm²
Charge = 28.7 nC
We need to calculate the flux of the electric field through the surface
Using formula Gauss's law
The electric flux through any closed surface,
Where, q = charge
Put the value into the formula
Hence, The flux of the electric field through the surface is 3.24\times10^{3}\ Nm^/C[/tex].
The manipulated variable is changed by the responding variable
It will act upon a buoyant force on the magnitude of which is equal to weight of the fluid
Answer:
0.208 N
Explanation:
Parameters given:
Current, I = 2A
Angle, A = 60°
Magnetic field strength, B = 0.2 T
Length, L = 0.6 m
Magnetic force is given as:
F = I * L * B * sinA
F = 2 * 0.6 * 0.2 * sin60
F = 0.24 * sin60.
F = 0.208 N