All categories

3 years ago

What are similarities and differences of the 1st, 2nd, and 3rd class levers?

1 answer:

7 0

Similarities:
-- All three classes have a fulcrum (pivot).
-- All three classes have a point where the effort force is applied.
-- All three classes have a point where the load or resistance force is applied.
-- If you can find a place to stand and a lever that's long enough,
then you can move the Earth with a 1st or 2nd Class lever.

Differences:
-- The mechanical advantage of a 1st Class lever
can be greater than 1, equal to 1, or less than 1.
-- The mechanical advantage of a 2nd Class lever is always more than 1 .
-- The mechanical advantage of a 3rd Class lever is always less than 1 .

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The pressure in a water line is 1500 kpa. what is the line pressure in (a) lb/ft2 units and (b) lbf/in2 (psi) units?

kotegsom [21]

To solve this problem, we know that:

1 psi = 6894.76 Pa

1 lb / ft^2 = 47.88 Pa

Therefore:

a. 1500 x 10^3 Pa * (1 lb / ft^2 / 47.88 Pa) = 31,328.32 lb / ft^2

b. 1500 x 10^3 Pa * (1 psi / 6894.76 Pa) = 217.56 psi

7 0

3 years ago

Read 2 more answers

The swinging pendulum has 10 joules of potential energy at its maximum height at points (1) and (5). If the mass of the pendulum

SVEN [57.7K]

The speed of the pendulum at point 3 is 1.4 m/s

Explanation:

We can solve this problem by using the law of conservation of energy. In fact, the mechanical energy of the pendulum (which is the sum of his potential energy + his kinetic energy) must be conserved. So we can write:

$U_1 +K_1 = U_3 + K_3$

where

$U_1$ is the initial potential energy, at the highest position

$K_1$ is the initial kinetic energy, at the highest position

$U_3$ is the final potential energy, at the lowest position

$K_3$ is the final kinetic energy, at the lowest position

We are told that:

$U_1 = 10 J$ is the potential energy of the pendulum at the maximum height

$K_1 = 0$ (when the pendulum is at maximum height, the speed is zero, so the kinetic energy is zero)

$U_3 = 0$ (potential energy is zero at the lowest position)

Therefore,

$K_3 = U_1 = 10 J$

Kinetic energy can be rewritten as

$K_3 = \frac{1}{2}mv^2$

where

m = 10 kg is the mass of the pendulum

v is its speed at point 3

Solving for v,

$v=\sqrt{\frac{2K_3}{m}}=\sqrt{\frac{2(10)}{10}}=1.4 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

4 0

3 years ago

Balanced or Unbalanced?

Galina-37 [17]

Unbalanced because if it is pushing then stopping, that means that it is unbalanced.

6 0

3 years ago

One strategy in a snowball fight is to throw

Oxana [17]

second question: How many seconds after the first snowball

should you throw the second so that they

arrive on target at the same time?

Answer in units of s.

Answer:

Part 1: 28°

Part 2: 1.367

Explanation:

Part 1:

Given: 62°

Simple

θ = 90°- 62°

Part 2:

Y-direction

Δy $=v_{yo} t+\frac{1}{2} a_{y} t^{2}$

$0=[16.2sin(62)]t_{1}+1/2(-9.8)t_{1}^{2} \\$

$t_{1} =\frac{2[16.2sin(62)]}{9.8}$

$t_{1}=2.91913s$

$0=[16.2sin(28)]t_{2}+1/2(-9.8)t_{2}^{2}$

$t_{2} =\frac{2[16.2sin(28)]}{9.8}$

$t_{2}=1.55213s$

Δt $=t_{1}-t_{2}$

Δt $=2.91913-1.55213$

Hope it helps :)

7 0

3 years ago

A liquid has a density of 0.85 g/cm. If you pour some of the liquid into a glass of water, will the liquid float?

muminat

Answer:

Yes, it will float.

Explanation:

It is given that,

A liquid has a density of 0.85 g/cm³.

We know that, the density of water is 1 g/cm³.

The density of the liquid is less than that of water. If the density of the liquid is less than that of water, it will float in it. Hence, if you pour some of the liquid into a glass of water, it will float.

4 0

3 years ago