Answer:
Option C. Objects 1 and 3 will not move, and objects 2 and 4 will accelerate
upward.
Explanation:
The following data were obtained from the question:
OBJECT >>>>>>>>> WEIGHT (N)
1 >>>>>>>>>>>>>>>> 35
2 >>>>>>>>>>>>>>>> 23
3 >>>>>>>>>>>>>>>> 26
4 >>>>>>>>>>>>>>>> 18
Force (F) applied = 25 N
From the above, the force applied to each object is 25N. Thus the following can be concluded based on the data given above:
For object 1:
Weight = 35 N
Force applied = 25 N
Thus, the object will not move since the weight of the object is greater than the force applied
For object 2:
Weight = 23 N
Force applied = 25 N
Thus, the object will move since the force applied is greater than the weight of the object.
For object 3:
Weight = 26 N
Force applied = 25 N
Thus, the object will not move since the weight of the object is greater than the force applied.
For object 4:
Weight = 18 N
Force applied = 25 N
Thus, the object will move since the force applied is greater than the weight of the object.
From the above illustrations, Object 1 and 3 will not move, and objects 2 and 4 will accelerate i.e move
Answer:
due to condection of heat from pan in thermal energy according to 9th
Explanation:
Answer:
Minimum thickness will be 100 nm
Explanation:
We have given refractive index is n = 1.5
Wavelength of the light incidence 
= 600 nm
We have to find the smallest thickness of the film so that there will be minimum light reflect
For minimum thickness of non reflecting film
, here t is thickness, is wavelength and n is refractive index
Putting all values 
So minimum thickness will be 100 nm
Answer:
L = 1.15 m
Explanation:
The diffraction phenomenon is described by the equation
a sin θ = m λ
Where a is the width of the slit, λ the wavelength and m is an integer, the order of diffraction is left.
The diffraction measurements are made on a screen that is far from the slit, and the angles in the experiment are very small, let's use trigonometry
tan θ = y / L
tan θ = sint θ / cos θ≈ sin θ
We substitute in the first equation
a (y / L) = m λ
The first maximum occurs for m = 1
The distance is measured from the center point of maximum, which coincides with the center of the slit, in this case the distance is the total width of the central maximum, so the distance (y) measured from the center is
y = 1.15 / 2 = 0.575 cm
y = 0.575 10⁻² m
Let's clear the distance to the screen (L)
L = a y / λ
Let's calculate
L = 115 10⁻⁶ 0.575 10⁻² / 575 10⁻⁹
L = 1.15 m
