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TiliK225 [7]
3 years ago
8

What is the fleas acceleration as it extends its legs

Physics
1 answer:
valina [46]3 years ago
3 0
When a flea jumps it reaches a takeoff speed of 1.0 m/s over a distance of 0.50mm

hope its right :)
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7 Calculate the weight of an apple of mass 100 grams
Leni [432]

Answer:

See the anwers below

Explanation:

To solve this problem we must understand that the weight of anyW = 0.1*10\\W = 1 [N]body is defined as the product of mass by gravitational acceleration. Gravitational acceleration depends on the place in space where a certain body is located.

W = m*g\\

where:

W = weight [N]

m = mass = 100 [g] = 0.1 [kg]

g = gravity acceleration [m/s²] or [N/kg]

<u>Now for the Earth</u>

<u />W =m*g\\W =0.1*10\\W = 1[N]<u />

<u>For the Moon</u>

<u />W = m*g\\W =0.1*1.6\\W = 0.16 [N]<u />

4 0
3 years ago
Which statement best describes how scientists and engineers work together in the research and development cycle? A. Scientists t
Pavlova-9 [17]

Answer:

c

Explanation:

7 0
4 years ago
Read 2 more answers
If a transformer has 50 turns in the primary winding and 10 turns on the secondary winding, what is the reflected resistance in
Elza [17]

Answer:

The reflected resistance in the primary winding is 6250 Ω

Explanation:

Given;

number of turns in the primary winding, N_P = 50 turns

number of turns in the secondary winding, N_S = 10 turns

the secondary load resistance, R_S = 250 Ω

Determine the turns ratio;

K = \frac{N_P}{N_S} \\\\K = \frac{50}{10} \\\\K = 5

Now, determine the reflected resistance in the primary winding;

\frac{R_P}{R_S} = K^2\\\\R_P = R_SK^2\\\\R_P = 250(5)^2\\\\R_P = 6250 \ Ohms

Therefore, the reflected resistance in the primary winding is 6250 Ω

6 0
4 years ago
Choose the letter for the acceleration of the ball during the upward motion after it is released. a) The acceleration is in the
lianna [129]

Answer:

Option (a)

Explanation:

If a body is thrown upwards, it's velocity goes on decreasing with constant rate. It is because an acceleration is acting on the body which is equal to acceleration due to gravity and acting downwards. The value of acceleration due to gravity is constant and always acting downwards.

8 0
4 years ago
A small object with a 5.0-mC charge is accelerating horizontally on a friction-free surface at 0.0050 m/s2 due only to an electr
kolbaska11 [484]

Answer:

0.002 N/C

Explanation:

Parameters given:

Charge of object, q = 5 mC = 5 * 10^{-3} C

Acceleration of object, a = 0.005 m/s^2

Mass of object, m = 2.0 g

The Electric field exerts a particular force on the object, causing it to accelerate (Electrostatic force).

We know that Electrostatic force, F, is given in terms of Electric field, E, as:

F = qE

This means that the object exerts a force of -qE on the Electric force (Action with equal and opposite reaction).

The object also has a force, F, due to its acceleration a. This force is the product of its mass and acceleration. Mathematically:

F = ma

Equating the two forces of the object, we get:

-qE = ma

=> E = \frac{-ma}{q}

Solving for E, we have:

E = \frac{-2 * 10^{-3} * 0.005}{5 * 10^{-3}} \\\\\\E = -0.002 N/C

The magnitude will be:

|E| = |-0.002| N/C = 0.002 N/C

The electric field has a magnitude of 0.002 N/C.

4 0
4 years ago
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