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krok68 [10]
3 years ago
8

Which travels fastest through empty space? A. electromechanical waves B. transverse waves C. longitudinal waves D. electromagnet

ic waves
Physics
1 answer:
Nady [450]3 years ago
7 0
The answer is B hope it helps:)
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Which factor affects the force of gravity between objects? Check all that apply. A.direction
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The gravitational force between two masses is given by the formula

F=G\dfrac{Mm}{r^2}

where G is the <em>gravitational constant, </em>M is the larger mass, m is the smaller mass, and r is the distance between the centers of the objects. The values we can change here to affect that gravitational force are the <em>mass </em>and the <em>distance</em>. Time and shape have no impact on this force.

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A student constructed a simple electric circuit where two light bulbs were connected in parallel. The circuit power source was a
Natasha2012 [34]

Answer:

RT =  17 ohms

Explanation:

For two parallel resistances in a circuit the combined resistance is given by:

\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}\\\\\frac{1}{R_T}=\frac{R_2+R_1}{R_1R_2}\\\\R_T=\frac{R_1R_2}{R_1+R_2}

R1 = 25 ohms

R2 = 50 ohms

You replace the values of R1 and R2 in the formula for RT:

R_T=\frac{(25)(50)}{25+50}ohms=16.66\ ohms \approx 17\ ohms

hence, the combined resitances is 17 ohms

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Describe how you can you use a graduated cylinder to measure the volume of an irregular object​
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Answer:Place the graduated cylinder on a flat surface and view the height of the liquid in the cylinder with your eyes directly level with the liquid. The liquid will tend to curve downward. This curve is called the meniscus. Always read the measurement at the bottom of the meniscus.

Explanation:

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A 2.00 meter long horizontal plank whose mass is 3.00 kg is placed so that the very end (the right end) rests on a retaining wal
avanturin [10]

Answer:

R_g=\frac{61}{7} =8.7143\ N

R_w=45.1857\ N

Explanation:

Given that:

  • mass of plank, m=3\ kg
  • length of plank, l=2\ m

From the image we can visualize the given situation.

Consider the given plank to be mass-less and having a uniformly distributed mass of 1.5 kg per meter.

<u>Now in the balanced condition:</u>

  • \sum F=0

R_g+R_w=(3+2.5)\times 9.8

R_g+R_w=53.9\ N .......................(1)

  • \sum M_w=0

1.75\times R_g=3\times 1+(2.5\times 9.8)\times 0.5

R_g=\frac{61}{7} =8.7143\ N ...........................(2)

is the force acted by the tailgate on the plank.

<u>Substitute the value from (2) into (1):</u>

R_w=45.1857\ N is the force acted by the wall upon the plank.

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3 years ago
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