Yes, we can dissolve 35 moles of KMnO₄ into 500 mL of water to give a molarity of 70 M
<h3>What is molarity? </h3>
Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the molarity </h3>
- Mole of KMnO₄ = 35 moles
- Volume = 500 mL = 500 / 1000 = 0.5 L
Molarity = mole / Volume
Molarity = 35 / 0.5
Molarity = 70 M
Learn more about molarity:
brainly.com/question/9468209
There are 2 molecules indicated
Answer:
4.5 times 10 = 45
Explanation:
"Non-zero digits are always significant. Any zeros between two significant digits are significant. A final zero or trailing zeros in the decimal portion ONLY are significant."
Answer:
Unchanged.
Explanation:
Hello,
In this case, for the experiment you performed, as you previously removed the sodium chloride, its % salt calculation will not be affected by the lost of the sand. It is important to remember that such experiments must be performed carefully as the committed error is a high-impact factor regarding to the experiment's performance. It is important for you to remember that to separate the sodium chloride, it earlier dissolution in water allowed to be dissolved leveraging the insolubility of sand in water, thus, it was decanted easily.
Best regards.
<span>HCl + MnO2 → MnCl2 + H2O + Cl2
In order to balance this, we have to have the same number of electrons of each element on both sides. Here's how to do it:
4HCl + MnO2 </span>→ MnCl2 + 2H2O + Cl2
You can see that now there are 4 atoms of H on the left, and 4 on the right (left: 4H, right 2H2 = 4H). The number of electrons for Mn is 1 on both sides, and for O is 2 on both sides. For Cl, on the left, there are 4 electrons, and on the right there are 4 as well (left: 4Cl, right: Cl2 + Cl2 = 4Cl).
So, based on this, the coefficient for HCl is D. 4.
