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3 years ago

11

You and your band want to record a CD in your basement. What might you need to do to make your basements a good place or recordi

ng music?

1 answer:

Nuetrik [128]3 years ago

5 0

Room that wont bother other people... instruments a stereo, and a sound system

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A constant friction force of 25 N acts on a 65-kg skier for 15 s on level snow. What is the skier’s change in velocity

nikdorinn [45]

Answer:

$\Delta v=5.77m/s$

Explanation:

Newton's 2nd Law relates the net force <em>F</em> on an object of mass <em>m </em>with the acceleration <em>a</em> it experiments by <em>F=ma.</em> In our case the net force is the friction force, since it's the only one the skier is experimenting horizontally and the vertical ones cancel out since he's not moving in that direction. Our acceleration then will be:

$a=\frac{F}{m}$

Also, acceleration is defined by the change of velocity $\Delta v$ in a given time t, so we have:

$a=\frac{\Delta v}{t}$

Since we want the change in velocity, <em>mixing both equations</em> we conclude that:

$\Delta v=at=\frac{Ft}{m}$

Which for our values means:

$\Delta v=\frac{Ft}{m}=\frac{(25N)(15s)}{(65Kg)}=5.77m/s$

4 0

3 years ago

Is the speed of the object is zero when it's at rest ?

NARA [144]

Yes! Although the object has potential energy, the object is not moving and therefore has no speed. :)

4 0

3 years ago

Im a freshman in highschool pls help

Vsevolod [243]

Well I can help you with some...
1. The answer is 2 Hydrogen and 2 Oxygen
3. 4 Hydrogen and 2 Oxygen
4. 16 Hydrogen and 16 Oxygen
6. 2 H2O
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3 years ago

A 2.0 kg block is pushed 1.0 m at a constant

svet-max [94.6K]

1) Work done by the force: 8.3 J

2) Work done by gravity: -19.6 J

3) Normal force: 16.3 N

Explanation:

1)

The work done by a force pushing an object is given by

$W=Fd cos \alpha$

where

F is the magnitude of the force

d is the displacement of the object

$\alpha$ is the angle between the direction of the force and of the displacement

First of all, we need to find the magnitude of the force F. Since the block is moving vertically at constant velocity (= zero acceleration), the equation of motion of the block along the vertical direction is:

$F sin \theta - \mu N - mg = 0$ (1)

Where

$\theta=27.0^{\circ}$

$\mu N$ is the force of friction, where

$\mu=0.40$ is the coefficient of friction

N is the normal reaction of the wall

(mg) is the weight of the block, where

m =2.0 kg is the mass of the block

$g=9.81 m/s^2$ is the acceleration of gravity

Along the horizontal direction, the equation of motion is:

$F cos \theta = N$ (2)

Substituting (2) into (1),

$F sin \theta - \mu F cos \theta - mg =0$

And solving for F,

$F(sin \theta - \mu cos \theta) = mg\\F=\frac{mg}{sin \theta - \mu cos \theta}=\frac{(2.0)(9.81)}{sin 27^{\circ} - 0.40 cos 27^{\circ}}=18.3 N$

Now we can calculate the work done by the force. Here we have

d = 1.0 m is the displacement

$\alpha = 90^{\circ} - 27^{\circ} = 63^{\circ}$ is the angle between the direction of the force and the displacement

Substituting,

$W=(18.3)(1.0)(cos 63^{\circ})=8.3 J$

2)

The work done by gravity is equal to:

$W_g = mg d cos \alpha$

where

m = 2.0 kg is the mass of the block

$g=9.81 m/s^2$

d = 1.0 m is the displacement

$\alpha=180^{\circ}$ , since the direction of gravity is downward while the displacement of the block is upward

Substituting,

$W=(2.0)(9.81)(1.0)(cos 180^{\circ})=-19.6 J$

3)

Equation (2) found in part 1) tells that

$N=F cos \theta$

which means that the normal force between the wall and the block is equal to the horizontal component of the pushing force on the block.

Here we have:

F = 18.3 N is the magnitude of the pushing force

$\theta=27.0^{\circ}$ is the angle of the force with the horizontal

Substituting, we find the normal force:

$N=(18.3)(cos 27^{\circ})=16.3 N$

Learn more about forces and acceleration:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

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3 years ago

Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition react

kotegsom [21]

2LiCl + 3O2

is the answer

5 0

3 years ago

Read 2 more answers