The calculated mutual inductance is 8.544 x 10⁻⁵ H.
Two coils have a mutual inductance of 1 henry when emf of 1 volt is induced in coil 1 and when the current flowing through coil 2 is changing at the rate of one ampere per second.
Length of the solenoid= 5.0 cm
Area of cross-section=1.0 cm²
no of spaced turns=300 turns
turns of insulated wire=180 turns
Mutual inductance (M) = μ₀μr N1N2 A/ L
=(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5
=79.12 x 10⁻¹⁰ x 54000 / 5
=8.544 x 10⁻⁵ H
hence, the mutual inductance is 8.544 x 10⁻⁵ H.
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The scientific unit for speed is kilometers per hour, hope this helps
Answer:
a. T₂ = 901.43 ° K
b. T₂ = 843.85 ° K
Explanation:
Given
η = 0.165 mol , Q = 690 J , V = 280 cm³ , P = 3.40 x 10 ⁶ Pa , T₁ = 700 ° K
Using the equation that describe the experiment of heat
Q = η * Cv * ΔT
a.
Nitrogen Cv = 20.76 J / mol ° K
ΔT = T₂ - T₁
T₂ = [ Q / ( η * Cv) ] + T₁
T₂ = [ 690 J / ( 0.165 mol * 20.76 J / mol ° K ) ] + 700 ° K
T₂ = 901.43 ° K
b.
Nitrogen Cp = 29.07 J / mol ° K
T₂ = [ Q / ( η * Cv) ] + T₁
T₂ = [ 690 J / ( 0.165 mol * 29.07 J / mol ° K ) ] + 700 ° K
T₂ = 843.85 ° K
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•Since the log is stationary and you are moving beside the log, it seems to move in the opposite direction from your point of view, because from your perspective u are stationary and the log is moving. If you were to stop moving the log would also stop moving.
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