One of the element carbon combines with one of the element oxygen to form one of the compound carbon dioxide.
2 answers:
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Answer:
the work done by the motor is 531,45 Joules
Explanation:
Using a sketch of the possible conditions, we need to find the distance that the block was moved, in order to find the work done by the electrical motor.
The sketch could be seen in the attached image.
Answer:
this may be wrong but I am not sure
Answer:
1) The magnitude of the angular acceleration = 67.92 rad/
2) Magnitude of the linear acceleration = 2.744 m/
3) How long does it take the bowling ball to begin rolling without slipping = 0.906 s
4) How long does it take the bowling ball to begin rolling without slipping = 6.75 m
5) the final velocity is 6.21 m/s
Explanation:
the given information :
Bowling mass m = 3.6 kg
Radius = 0.101 m
Initial speed = 8.7 m/s
Coefficient of kinetic friction μ = 0.28
1) he magnitude of the angular acceleration of the bowling ball is
F = m a
= μ N , N = m g
= μ m g
1) The magnitude of the angular acceleration of the bowling ball as it slides down the lane:
momen inersia of Bowling ball I = (2/5) m
torque τ = I α
τ = F R
I α = F R
(2/5) m α = μ m g R
α = (5 μ g / 2R) μ g R
= (5 x 0.28 x 9.8/ 2 x 0.101)
= 67.92 rad/
2) Magnitude of the linear acceleration of the bowling ball as it slides down the lane
F = - ,
is the force of kinetic friction
m a = - μ m g, remove m
the magnitude of linear accelaration is
a = μ g
= (0.28) (9.8)
= 2.744 m/
3) The bowling ball takes time to begin rolling without slipping:
The linear speed, =
- a t
=
- μ g t
the angular speed, ω = ω0 + α t
ω = ω0 + (5 μ g/2R ) t
= ω R
- μ g t = ω0 R + (5 μ g/2R ) t R
7 μ g t/2 = + ω0 R
hence,
t = (2 + ω0 R)/ 7 μ g
ω0 = 0 (no initial spin), therefore
t = 2 / 7 μ g
= 2 x 8.7 / 7 (0.28) (9.8)
= 0.906 s
4) How long it takes for the bowling ball to begin rolling without slipping, S
S = t - (1/2) a
= (8.7) (0.906) - (1/2) (2.744)
= 6.75 m
5) The final velocity
=
- a t
= 8.7 - (2.744) (0.906)
= 6.21 m/s