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3 years ago

One of the element carbon combines with one of the element oxygen to form one of the compound carbon dioxide.

Physics

2 answers:

Bogdan [553]3 years ago

5 0

the answer is atom,molecule,molecule

saul85 [17]3 years ago

3 0

False. C + O --> CO not CO2. Carbonmonoxide

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A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir

Fantom [35]

Answer:

linear charge density = -9.495 × $10^{-34}$ C/m

Explanation:

given data

revolutions per second = 1.80 × $10^{6}$

radius = 1.20 cm

solution

we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force

- q × E = m × w² × r ..................1

- 9 × $10^{9}$ × $\frac{2*linear\ charge\ density}r}$ q = m × w² × r ............2

and w = $\frac{2*\pi}{T}$

w = $\frac{d\theta }{dt}$

w = 1.80 × $10^{6}$ × $\frac{2*\pi}{1}$

w = 11304000 rad/s

so here from equation 2

- 9 × $10^{9}$ × $\frac{2*linear\ charge\ density}{0.012}$ 1.80 × $10^{6}$ = 1.672 × $10^{-27}$ × 11304000² × 0.0120

linear charge density = -9.495 × $10^{-34}$ C/m

8 0

2 years ago

A runner of mass 80 kg is moving at 8.0 m/s. Calculate her kinetic energy.

lana [24]

Answer:

2560J

Explanation:

By definition the kinetic energy can be calculated in the following way:

K = (mv²)/2 = 80kg·(8.0m/s)²/2 = 2560 J

7 0

2 years ago

It can take some of those large , industrial vehicles up to ____ feet to stop when traveling only 60 MPH, and therefore , you sh

kherson [118]

Answer:

a 200 feet, and trains go a whole mile even after hitting the brakes

Explanation:

4 0

3 years ago

A car with a mass of 2200 kg is travelling at a rate of 55 m's. What is the cars momentum? *

Varvara68 [4.7K]

Mass=2200kg
Velocity=55m/s

$\\ \sf\bull\dashrightarrow Momentum=Mass\times Velocity$

$\\ \sf\bull\dashrightarrow Momentum=2200(55)$

$\\ \sf\bull\dashrightarrow Momentum=121000kgm/s$

7 0

2 years ago

Read 2 more answers

A power plant produces 1000 MW to suply a city 40Km away.Current flows from the power plant on a single wire of resistance0.050

Westkost [7]

Answer:

The current in wire resistance 2Ω

a). 8696 A

b). fraction power 15.1% a 115kV

Explanation:

Resistance

$R=0.05$ Ω/Km*40km

R=2Ω

P=1000 MW

a).

$P=V*I\\I=\frac{P}{V}=\frac{1000x10^{6}W}{115x10^{3}k } =8696.65A$

Using law ohm

b).

$V=I*R\\I=\frac{V}{R}$

$P=I*I*R\\P=I^{2} *R\\P=8696.65^{2}*2\\P=151.228 x10^{6} W$

$e=\frac{151.228x10^{6} }{1000x10^{6} }*100= 15.12$ %

8 0

3 years ago