A uniform rod of length L rests on a frictionless horizontalsurface. The rod pivots about a fixed, frictionless axis at oneend.
the rod is initially at rest. A bullet travelling parallel tothe horizontal surface and perpendicular to the rod with speed vstrikes the rod at its center and becomes embedded in it. The massof the bullet is one-fourth the mass of the rod. a) What is thefinal angular speed of the rod? b) What is the ratio of the kineticenergy of teh system after the collision to the kinetic energy ofthe bullet before the collision?
1 answer:
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Answer:
c. The coefficient of kinetic friction is less than the coefficient of static friction
Explanation:
When the box finally does break loose. Then the component of the box weight which is parallel to the board weight parallel component, is equal to the .
For the box to acce;erate thee must be non-zero net force acting on the box parallel to the board. Or we can say,
Therefore the force of kinetic friction must be less than the force of static friction. Thus,
From the diagram we have that
Therefore the direction is 30° from east of south
