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iVinArrow [24]
3 years ago
7

A uniform rod of length L rests on a frictionless horizontalsurface. The rod pivots about a fixed, frictionless axis at oneend.

the rod is initially at rest. A bullet travelling parallel tothe horizontal surface and perpendicular to the rod with speed vstrikes the rod at its center and becomes embedded in it. The massof the bullet is one-fourth the mass of the rod. a) What is thefinal angular speed of the rod? b) What is the ratio of the kineticenergy of teh system after the collision to the kinetic energy ofthe bullet before the collision?

Physics
1 answer:
coldgirl [10]3 years ago
5 0

Answer: a ) 6/19 V/L

b ) 3/19

Explanation:

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PART ONE
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1. F = 45,458.17 N

2. P = 12,800,000 W

Explanation:

Part 1. The thrust force is the sum of the forces on the air and on the fuel.

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F = (107 kg) (679 m/s − 281 m/s) / (1 s)

F = 42,586 N

For the fuel, 4.23 kg of fuel is accelerated from 0 m/s to 679 m/s in 1 second.

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F = 45,458.17 N

Rounded to three significant figures, the force is 45,500 N.

Part 2. Power = work / time, and work = force × distance, so:

Power = force × distance / time

Power = force × velocity

P = (45,458.17 N) (281 m/s)

P = 12,773,745.77 W

Rounded to three significant figures, the power is 12,800,000 W.

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