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Keith_Richards [23]
3 years ago
11

At what point is its PE a maximum? 1. midway between the highest and lowest points 2. at the highest point 3. at the lowest poin

t 4. The PE does not change.
Physics
1 answer:
zavuch27 [327]3 years ago
7 0

Answer:

2. at the highest point

Explanation:

For a generic object, the PE (gravitational potential energy) is defined as

PE = mgh

where

m is the mass of the object

g is the gravitational acceleration

h is the height of the object with respect to the ground

From the formula, we see that PE is maximum when h is maximum: so the PE is maximum when the object is at the highest point.

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The mass of a proton is approximately equal to
Dahasolnce [82]

Answer:

1.6726\cdot 10^{-27} kg

Explanation:

The three main particles that make an atom are:

- Proton: its mass is 1.6726\cdot 10^{-27} kg, it carries an electric charge of +e (e=1.6\cdot 10^{-19}C), and it is located in the nucles of the atom

- Neutron: its mass is 1.6749 \cdot 10^{-27}kg, it carries no electric charge, and it is also located in the nucleus of the atom

- Electron: its mass is 9.1094 \cdot 10^{-31}kg, it carries an electric charge of -e (e=1.6\cdot 10^{-19}C), and it is located outside the nucleus

3 0
3 years ago
An object with a mass of 5kg accelerates at 2m/s2. How much force in Newtons(N) is needed to cause this to happen??
Reptile [31]

Answer: The formula of Newtons second law of motion is F=MA so therefore it would be written like this Force = Mass X Acceleration

F = 5 x 2

F = 10 N

6 0
3 years ago
How much is the plane's acceleration while breaking if it takes 15 s for its velocity
Marizza181 [45]

Answer:

A. 4.67 m/s²

Explanation:

u = 145 m/s

v = 75 m/s

t = 15 s

a = v - u / t

= 145 - 75 / 15

= 4.67 m/s²

Hope this helped...

7 0
3 years ago
what is the dot product and cross product of of two vectors if the angle is between them is 90 degree?​
DaniilM [7]

\sf{\pink{\underline{\underline{\blue{GIVEN:-}}}}}

  • The angle between the two vectors is 90° .

\sf{\pink{\underline{\underline{\blue{TO\: FIND:-}}}}}

  1. The dot product of two vectors .
  2. The cross product of two vectors .

\sf{\pink{\underline{\underline{\blue{SOLUTION:-}}}}}

⚡ Let \rm{\vec{a}} and \rm{\vec{b}} are the two vectors .

✍️ We have know that,

\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:.\:\vec{b}\:=\:ab\cos{\theta}\:}}}}

Where,

  • θ = 90°

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\cos{90^{\degree}}\:}

  • cos 90° = <u>0</u>

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\times{0}\:}

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:0\:}

\rm{\red{\therefore}} [1] The dot product of two vectors is “ <u>0</u> ” .

✍️ We have know that,

\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:\times\:\vec{b}\:=\:ab\sin{\theta}\:}}}}

Where,

  • θ = 90°

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\sin{90^{\degree}}\:}

  • sin 90° = <u>1</u>

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\times{1}\:}

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\:}

\rm{\red{\therefore}} [2] The cross product of two vectors is “ <u>ab</u> ” .

3 0
3 years ago
Read 2 more answers
Does every light source emit only one type of light?
blsea [12.9K]

Yes it is possible. Spectrum of emitted light depends upon the chemical composition of the source. and the way of its excitation. a clear example to us is that of sun.

3 0
2 years ago
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