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HACTEHA [7]
3 years ago
7

Solve 3/4≤1/2+n. Graph the solution.

Mathematics
1 answer:
Nuetrik [128]3 years ago
5 0

The solution is n\geq\frac{1}{4}.

Solution:

Given expression:

$\frac{3}{4} \leq \frac{1}{2}+n

To solve this inequality.

$\frac{3}{4} \leq \frac{1}{2}+n

Subtract \frac{1}{2} on both sides of the inequality.

$\frac{3}{4}-\frac{1}{2} \leq \frac{1}{2}+n-\frac{1}{2}

$\frac{1}{4} \leq n

Switch the sides.

$n\geq\frac{1}{4}

The solution is n\geq\frac{1}{4}.

Now, graph the solution.

The solution of the graph is attached below.

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2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!
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To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
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3 years ago
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dem82 [27]

Answer:

B

Step-by-step explanation:

Rewriting in slope-intercept form.

x - 2y = 0

Add -x on both sides.

- 2y = 0 - x

Divide both sides by -2.

y = 0/-2 - x/-2

y = 0 - - 1/2x

y = 0 + 1/2x

y = 1/2x + 0

The slope is 1/2, the y-intercept is at (0, 0).

6 0
2 years ago
Complete the statement with equal to greater than or less than 5/5 * 2 3/4​
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3 0
3 years ago
I really need help with this
Sedbober [7]

Answer:

A. ∠1 = 105°

B. ∠2 = 105°

C. ∠1 = 105°

Step-by-step explanation:

We are given the angle made by the 4th street with King's Avenue is 75° as shown in the figure below.

Ques A: It is given that, Car travelling west on the 4th street turns towards south on the King's Avenue.

So, the required angle is ∠1.

Since, The sum of angles formed on a straight line is 180°.

Then, ∠1 + 75° = 180° i.e. ∠1 = 180-75 = 105°

Thus, ∠1 = 105°

Ques B: It is given that, Car travelling southwest on King's Avenue and turns right on 3rd street.

So, the required angle is ∠2.

<em>We have, 'Corresponding anges of two parallel lines are equal' and 'The sum of angles formed on a straight line is 180°.</em>

Then, ∠2 + 75° = 180° i.e. ∠2 = 180-75 = 105°

Thus, ∠2 = 105°

Ques C: It is given that, Car travelling northeast on King's Avenue and turns right on 4th street.

So, the required angle is ∠1.

Since, The sum of angles formed on a straight line is 180°.

Then, ∠1 + 75° = 180° i.e. ∠1 = 180-75 = 105°

Thus, ∠1 = 105°

3 0
3 years ago
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