Ask question

Ask question

All categories

3 years ago

9

An atom of gadolinium has an atomic number of 64 and a mass number of 154. how many electrons, protons, and neutrons does it con

tain?

1 answer:

Svetllana [295]3 years ago

5 0

No. of protons = atomic number = 64
no. of neutrons = mass no. - no. of protons= 154 -64 = 90
no. of electrons = no. of protons = 64

You might be interested in

You place an object 36.0 cm in front of a concave

vivado [14]

<em><u>Given</u></em><em> </em> :

<em>O</em><em>bject </em><em>position</em><em> </em>( u ) = - 36 cm
<em>focal</em><em> </em><em>length</em><em> </em>( f ) = - 16 cm
<em>image position</em><em> </em>( v ) = ?

now, we know

=》

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

=》

$\frac{1}{ - 16} = \frac{1}{ - 36} + \frac{1}{v}$

=》

$\frac{1}{v} = \frac{ - 1}{16} - \frac{ - 1}{36}$

=》

$\frac{1}{v} = \frac{ - 9 - ( - 4)}{144}$

=》

$\frac{1}{v} = \frac{ - 9 + 4}{144}$

=》

$\frac{1}{v} = \frac{ -5}{144}$

=》

$v = \frac{144}{ - 5}$

=》

<em><u> $v = - 28.8$ </u></em>

So<em><u>, image position</u></em> = 28.8 cm, at same side of object .

8 0

3 years ago

Do your relationships tend to have this quality?

dedylja [7]

What quality? /////////

5 0

3 years ago

Read 2 more answers

A system gains 1500J of heat and 2200J of work is done by the system on its surroundings. Determine the change in internal energ

Rina8888 [55]

Answer:

-700

formula is heat gained - work done

7 0

3 years ago

QUESTION 2 DOK 3 A Thompson's gazelle has a maximum acceleration of 4.5 m/s2 At this acceleration, how much time is required for

Dominik [7]

Answer:

2.47 s

Explanation:

Convert the final velocity to m/s.

40 km/h → 11.1111 m/s

We have the acceleration of the gazelle, 4.5 m/s².

We can assume the gazelle starts at an initial velocity of 0 m/s in order to determine how much time it requires to reach a final velocity of 11.1111 m/s.

We want to find the time t.

Find the constant acceleration equation that contains all four of these variables.

v = v₀ + at

Substitute the known values into the equation.

11.1111 = 0 + (4.5)t
11.1111 = 4.5t
t = 2.469133333

The Thompson's gazelle requires a time of 2.47 s to reach a speed of 40 km/h (11.1111 m/s).

5 0

3 years ago

The quantity of heat Q that changes the temperature L1Tof a mass mof a substance isgiven by Q = cmt:T, where c is the specific h

White raven [17]

Answer:

a) Q = 80,000 cal

b) Q = 100,000 cal

c) Q = 540,000 cal

d) Q = 720,000 cal

Explanation:

a)1 kg from 0⁰ Ice to 0⁰ water, the heat produced is latent heat of fusion

$Q_{l} = ML_{f}$ = 1 * 80

$Q_{l}$ = 80 kCal = 80,000 cal

b) 1 kg of O°C ice water to 1 kg of 100°C boiling water

Specific heat capacity, c = 1000cal/kg.C

$Q_{c} = mc \delta T\\Q_{c} = 1 * 1000 * (100 - 0)\\Q_{c} =100000 cal$

c) 1 kg of 100°C boiling water to 1 kg of 100°C steam

Latent heat of vaporization is needed for this conversion

$Q_{v} = ML_{v} \\L_{v} = 540 kCal/kg\\Q_{v} =1* 540 \\Q_{v} = 540 kCal = 540000 cal$

d) 1 kg of O°C ice to 1 kg of 100°C steam.

Q = $Q_{L} + Q_{c} + Q_{v}$

Q = 80,000 + 100,000 + 540,000

Q = 720,000 cal

7 0

4 years ago