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4 years ago

9

An atom of gadolinium has an atomic number of 64 and a mass number of 154. how many electrons, protons, and neutrons does it con

tain?

1 answer:

Svetllana [295]4 years ago

5 0

No. of protons = atomic number = 64
no. of neutrons = mass no. - no. of protons= 154 -64 = 90
no. of electrons = no. of protons = 64

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Although there are different ways to approach a scientific investigation, all scientific investigations begin with some sort of

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Answer: hypothesis or guess

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4 years ago

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Which statement(s) correctly compare the masses of protons, neutrons, and electrons?

ZanzabumX [31]

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Neutrons and protons make up a nucleus and they are in the middle of an atom. Electrons surround the nucleus. Opposite charges attract each other. Because of this, protons do not attract other protons and electrons do not attract other electrons. Instead, protons attract electrons and electrons attract protons. When someone looks at the elements on the periodic table, they can see how many protons are present by looking at the atomic number. Since atoms have to have an equal amount of each, if an element contains 36 protons, it also has 36 electrons.

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3 years ago

4. Calculate the kinetic energy of a 4.7 kg object moving at a speed of 7 m/s. SHOW YOUR WORK

SashulF [63]

Answer:

$\boxed {\boxed {\sf 115.15 \ J}}$

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated with the following formula.

$E_K= \frac{1}{2} mv^2$

The mass of the object is 4.7 kilograms. The velocity of the object is 7 meters per second.

m= 4.7 kg
v= 7 m/s

Substitute the values into the formula.

$E_K= \frac{1}{2} (4.7 \ kg)(7 \ m/s)^2$

Solve the exponent.

(7 m/s)²= 7 m/s * 7 m/s = 49 m²/s²

$E_K= \frac{1}{2} (4.7 \ kg)(49 \ m^2/s^2)$

Multiply the numbers together.

$E_K = 2.35 \ kg * 49 \ m^2/s^2$

$E_K= 115.15 \ kg*m^2/s^2$

Convert the units. 1 kilogram square meter per square second is equal to 1 Joule.

$E_K= 115.15 \ J$

The object has <u>115.15 Joules</u> of kinetic energy.

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2 years ago

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A boat is subject to hydrodynamic drag forces of F = 40v 2 [N] where v is the magnitude of velocity in [m/s]. The boat’s mass is

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Answer:

It has moved a distance, S = 25.9 m

Explanation:

F = 40 v²........(1)

$F = mv\frac{dv}{dS}$ .........(2)

Equating (1) and (2)

$-mv\frac{dv}{dS} = 40 v^2\\\\v\frac{dv}{dS} = \frac{-40 v^2}{m} \\\\m = 450 kg\\v\frac{dv}{dS} = \frac{-40 v^2}{450}\\\\ \frac{dv}{v} = \frac{40}{450} dS\\$

Integrate both sides:

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$\int\limits^{10}_1 {\frac{1}{v} } \, dv = \frac{-40}{450} \int\limits^S_0 \, dS \\\\ln\frac{1}{10} = \frac{-40}{450} (S-0)\\\\S = \frac{-40}{450} ln(0.1)\\\\S = 25.9 m$ .

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3 years ago

A melon is projected into the air with 100 j of kinetic energy in the presence of air resistance. when it returns to its initial

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In the presence of air resistance, a watermelon is launched into the air with 100 j of kinetic energy.

Its kinetic energy is less than 100 J when it reaches its starting point. Its kinetic energy decreases as it encounters air resistance and returns to its starting point. In actuality, some of the energy has been lost because of air resistance. Since we use the ball's original height as a point of reference, there is no potential energy when the ball is in its initial state of motion, and K is its kinetic energy. This total energy is conserved if there is no air resistance, therefore when the ball returns to its starting position, its kinetic energy will remain at 100.

Learn more kinetic energy about here:

brainly.com/question/12669551

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1 year ago