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Montano1993 [528]
3 years ago
8

Find the magnitude of the vector 34 i^+ 14 j^m.

Physics
1 answer:
Tanya [424]3 years ago
6 0
I believe you square both numbers and take the square root. √34^2+14^2= so it would be 36.77
You might be interested in
A plane travels 2.5 KM at an angle of 35 degrees to the ground, then changes direction and travels 5.2 km at an angle of 22 degr
Solnce55 [7]

Answer:

7.7 km 26°

Explanation:

The total x component is:

x = 2.5 cos(35°) + 5.2 cos(22°) = 6.87

The total y component is:

y = 2.5 sin(35°) + 5.2 sin(22°) = 3.38

The magnitude is:

d = √(x² + y²)

d = 7.7 km

The direction is:

θ = atan(y/x)

θ = 26°

5 0
3 years ago
Which type of modulation is applied to radio-controlled toys?
Alenkinab [10]

Pulse type of modulation is applied to radio-controlled toys, therefore the correct answer is option D.

<h3>What is the frequency?</h3>

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

Toys controlled by remote control operate by emitting infrared radiation. These infrared rays have a frequency of 34–48 kilo Hertz.

Different types of modulations, such as frequency and amplitude modulation for transmitting and receiving video and music, are employed for other reasons.

Thus, the Pulse-type of modulation is applied to radio-controlled toys, therefore the correct answer is option D.

Learn more about frequency from here

brainly.com/question/14316711

#SPJ1

6 0
2 years ago
The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o
Leya [2.2K]
Answer:
frequency = 5.52 * 10² Hz

Explanation:
the equation that relates velocity, frequency and wavelength is:
velocity = frequency * wavelength

We are given that:
velocity = 331 m/sec
wavelength = 0.6 m

Substitute with the givens in the equation to get the frequency as follows:
velocity = frequency * wavelength
331 = frequency * 0.6
frequency = 331 / 0.6
frequency = 5.52 * 10² Hz

Hope this helps :)
4 0
3 years ago
A body moves due north with velocity 40 m/s. A force is applied
marshall27 [118]

Answer:

the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

Explanation:

The change in the momentum of a body, if the mass of the body is constant, is given by the following formula:

\Delta p=\Delta (mv)\\\\\Delta p=m\Delta v

p: momentum

m: mass

\Delta v:  change in the velocity

The sign of the change in the velocity determines the direction of rate of change. Then you have:

\Delta v=v_2-v_1

v2: final velocity = 35m/s

v1: initial velocity = 40m/s

\Delta v =35m/s-40m/s=-5m/s

Hence, the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

4 0
3 years ago
A certain speed boat weighs 4,283 N. It can accelerate from 0 to 20 m/s in 5 seconds. What is the mass of the boat?
soldi70 [24.7K]

Answer:1070.8

Explanation:

4 0
3 years ago
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