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4 years ago

Explain how energy is conserved when nuclear fission or fusion occurs

Physics

2 answers:

andriy [413]4 years ago

6 0

Answer:

The energy is conserved in the nuclear fission when the nuclear reactor mass releases the kinetic energy in the reaction and then source is known as the nuclear binding energy.

By using the Einstein mass energy equation that is E = m×c², we can easily determine the actual amount of the released energy. The nuclear fission is the process of subdividing the heavy mass of the atomic nucleus like uranium.

The nuclear fusion basically violate the law (Conservation of mass). During the nuclear fusion process the matter are not conserve because when the nuclei gets fuse then its mass are converted into the energy and then it is released.

ollegr [7]4 years ago

5 0

The mass lost in the nuclear reaction is all converted to energy.

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Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride.

Mashcka [7]

The amount of work which Sam does need to stop the boat is 784Joule if boat mass is 800kg and boat drift in 1.4m/sec.

We know that according to work-energy theorem, change in kinetic energy of the body from one speed to another is equivalent to amount of work done by all forces acting on the body.

So, here we can see that final speed of boat is =0m/sec since Sam need to stop it.

Initial speed of boat is 1.4m/sec.

Also, we know that kinetic energy is given by the below formula:

Kinetic energy=(1/2)mv²

where m is the mass of the body

and v is the speed of the body

Now, from work energy theorem, we get

=>W=(1/2)m $v^2_2$ - (1/2)m $v^2_1$

=>W=0-(1/2)×800×(1.4)²

=>W= - 400× 1.4 × 1.4

=>W = -400×1.96

=>W= -784Joule

Here negative sign denotes work has to done against the original motion of boat.

Hence, amount of work needs to be done by Sam is 784Joule.

To know more about work,visit here:

brainly.com/question/18094932

#SPJ4

3 0

1 year ago

When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq

Lilit [14]

Answer:60 gm

Explanation:

Given

initial velocity of ball $u=0$

Force exerted by racquet $F=540 N$

time period of force $t=5\ ms$

final velocity of ball $v=45\ m/s$

Racquet imparts an impulse to the ball which is given by

$J=F\Delta t=\Delta P$

$J=540\times \Delta t=m(45-0)$

$m=\frac{540\times 5\times 10^{-3}}{45}$

$m=60\ gm$

8 0

3 years ago

Physics multiple choice

Aleksandr-060686 [28]

10. b

11.d

12. b

13.e

I hope this helps

3 0

4 years ago

Read 2 more answers

“How bright would the sun appear to an observer on Earth if the sun were four times farther from Earth than it actually is? Expr

Alenkasestr [34]

Like a lot of other things, (gravity, sound, electrostatic force), brightness also decreases as the square of the distance.

When the source moves to a new position that's 4 times as far away, its apparent brightness becomes (1/4^2) its original value.

That's 1/16 .

4 0

4 years ago

The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 6.00 s, at which time it

8_murik_8 [283]

Answer:

16.035 revolutions

Explanation:

Part 1:

t = 6 s, f0 = 0 , f = 5 rps,

Let the number of revolutions be n1.

Use first equation of motion for rotational motion

w = w0 + α t

2 x 3.14 x 5 = 0 + α x 6

α = 5.233 rad/s^2

Let θ1 be the angle turned.

Use second equation of motion for rotational motion

θ1 = w0 t + 12 x α x t^2

θ1 = 0 + 0.5 x 5.233 x 6 x 6 = 94.194 rad

n1 = θ1 / 2π = 94.194 / 2 x 3.14 = 15 revolutions

Part 2:

f0 = 5 rps, f = 0, t = 13 s

Let the number of revolutions be n2.

Use first equation of motion for rotational motion

w = w0 + α t

0 = 2 x 3.14 x 5 + α x 13

α = - 2.415 rad/s^2

Let θ2 be the angle turned.

Use third equation of motion for rotational motion

w^2 = w0^2 + 2 x α x θ2

0 = 2 x 3.14 x 5 - 2 x 2.415 x θ2

θ2 = 6.5 rad

n2 = θ2 / 2π = 6.5 / 2 x 3.14 = 1.035 revolutions

total revolutions n = n1 + n2 = 15 + 1.035 = 16.035 revolutions

3 0

3 years ago