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Digiron [165]
2 years ago
5

A net force of 12.0 N causes an object to increase its speed from 15.0 m/s to 18.0 m/s during a 2.0 second interval. What is the

mass of the object?
Physics
1 answer:
Nat2105 [25]2 years ago
8 0

Answer:

Mass of object = 8kg

Explanation:

  • <em>Since</em><em> </em><em>a</em><em>=</em><em> </em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>v</em><em>/</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>t</em><em>,</em><em> </em><em>a</em><em>=</em><em> </em><em>(</em><em>1</em><em>8</em><em>-16</em><em>)</em><em>/</em><em>2</em>

<em>=</em><em> </em><em>1.5</em>

  • <em>And</em><em> </em><em>F</em><em>=</em><em>ma</em><em> </em>
  • <em>Force</em><em> </em><em>=</em><em>1</em><em>2</em>
  • <em>a</em><em>=</em><em> </em><em>1.5</em>
  • <em>m</em><em>=</em><em>?</em>

<em>You</em><em> </em><em>can</em><em> </em><em>now</em><em> </em><em>solve</em><em> </em><em>for</em><em> </em><em>your</em><em> </em><em>unknown</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>mass</em><em>.</em>

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Explanation:

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An object is 15 cm in front of a diverging lens with a
Rainbow [258]

A) See ray diagram in attachment (-6.0 cm)

By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = -10 cm is the focal length (negative for a diverging lens)

p = 15 cm is the distance of the object from the lens

Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

q=\frac{1}{-0.167 cm^{-1}}=-6.0 cm

B) The image is upright

As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:

h_i = - h_o \frac{q}{p}

where h_i, h_o are the size of the image and of the object, respectively.

Since q < 0 and p > o, we have that h_i >0, which means that the image is upright.

C) The image is virtual

As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.

This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

4 0
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Q = 116.8 J

Explanation:

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So here we will have

Q = n C_p \Delta T

here we know that

n = number of moles

n = \frac{1}{22.4}

n = 0.0446

for ideal diatomic gas molar specific heat capacity at constant pressure is given as

C_p = \frac{7}{2}R

now we have

Q = (0.0446)(\frac{7}{2}R)(90)

Q = 116.8 J

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Orbital resonances.

Hope this helps!
Please give Brainliest!
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