Answer:
3.38 grams of O2 will be produced
Explanation:
Step 1: Data given
Mass of NaClO3 = 7.50 grams
Mass of NaCl = 4.12 grams
Molar mass of NaClO3 = 106.44 g/mol
Molar mass of NaCl = 58.44 g/mol
Step 2: The balanced equation
2NaClO3(s) → 2NaCl(s) + 3O2(g)
Step 3: Calculate moles
Moles NaClO3 = mass NaClO3 / molar mass NaClO3
Moles NaClO3 = 7.50 grams / 106.44 g/mol
Moles NaClO3 = 0.0705 moles
Moles NaCl = 4.12 grams / 58.44 g/mol
Moles NaCl = 0.0705 moles
For 2 moles NaClO3 we'll have 2 moles NaCl and 3 moles O2
For 0.0705 moles NaClO3 we'll have 0.0705 moles NaCl and 3/2 * 0.0705 = 0.10575 moles O2
Step 4: Calculate mass O2
Mass O2 = moles O2 * molar mass O2
Mass O2 = 0.10575 moles * 32.0 g/mol
Mass O2 = 3.38 grams O2
3.38 grams of O2 will be produced
