When heated solid silver oxide decomposes into its elements
1 answer:
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Answer:
1. 1.34g
2. 1.19g
3. 0.49g
Explanation:Please see attachment for explanation
Answer : The molarity of chloride ion in the final solution is, 0.436 M
Explanation :
First we have to calculate the mole of and
.
Molar mass of NaCl = 58.9 g/mol
and,
Now we have to calculate the moles of chloride ion.
As, 1 mole of NaCl dissociates to give 1 mole of sodium ion and 1 mole of chloride ion.
So, 0.0118 mole of NaCl dissociates to give 0.0118 mole of sodium ion and 0.0118 mole of chloride ion.
and,
As, 1 mole of dissociates to give 1 mole of sodium ion and 2 mole of chloride ion.
So, 0.005 mole of dissociates to give 0.005 mole of sodium ion and (2×0.005=0.01) mole of chloride ion.
Now we have to calculate the total moles of chloride ion and volume of solution.
Total moles of chloride ion = 0.0118 + 0.01 = 0.0218 mol
Total volume of solution = 50.0 mL = 0.050 L
Now we have to calculate the molarity of chloride ion in the final solution.
Thus, the molarity of chloride ion in the final solution is, 0.436 M