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GrogVix [38]
3 years ago
12

When heated solid silver oxide decomposes into its elements

Chemistry
1 answer:
ollegr [7]3 years ago
5 0
Hi!

When Silver Oxide (Ag20) is heated, it decomposes into Silver and Oxygen.
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HElp me plzzzzz??????
iris [78.8K]

Answer:

The answer to your question is given below

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + 2HCl —> ZnCl2 + H2

Thus, we can write out the atoms present in both the reactant and the product by doing a simple head count. The atoms present are listed below:

Element >>> Reactant >>> Product

Zn >>>>>>>> 1 >>>>>>>>>> 1

H >>>>>>>>> 2 >>>>>>>>> 2

Cl >>>>>>>>> 2 >>>>>>>>> 2

4 0
2 years ago
In an aqueous chloride solution cobalt(ii) exists in equilibrium with the complex ion cocl42-. co2 (aq) is pink and cocl42-(aq)
liraira [26]

First you should know that the Principle of Le Chatelier states that <u>if a system in equilibrium is subjected to a change of conditions, it will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium.</u>

The variation of one or several of the following factors can alter the equilibrium condition in a chemical reaction:

  • Temperature
  • The pressure
  • The volume
  • The concentration of reactants or products

1. This reaction is: <u>a. exothermic</u>

The chemical equilibrium at issue is:

CoCl₄²⁻  ⇄   Co²⁺ + 4Cl⁻ + heat

<em>blue</em>            <em>pink</em>

The reaction of the question is <u>exothermic</u> because when adding heat (at high temperature) the equilibrium moves to the left since the blue color is strong which means that there are more reagent (CoCl₄²⁻) that product (Co²⁺). On the other hand, when extracting heat from the system (at low temperature) the equilibrium moves to the right since the pink color predominates and more product is present in the solution.

2. When the temperature is decreased the equilibrium constant, k: <u>c. remains the same.</u>

As mentioned above, <u>a system in equilibrium that is disturbed will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium. </u>In this way, the system will always remain in equilibrium and its equilibrium constant will remain constant. This is why, despite altering the temperature of the system, the equilibrium constant remains constant.

3. When the temperature is decreased the equilibrium concentration of Co²⁺:  <u>a. increases</u>

Again, the chemical equilibrium at issue is:

CoCl₄²⁻  ⇄   Co²⁺ + 4Cl⁻ + heat

As the reaction in question is exothermic when the temperature decreases, heat is extracted from the system. <u>To compensate this decrease in heat, the system will react by shifting the balance to the right, increasing the concentration of the products and, therefore, the concentration of Co²⁺.</u>

5 0
3 years ago
13. What is the symbol for Enthalpy change?
OverLord2011 [107]

Answer:

Explanation:

13 ) symbol of enthalpy change = Δ H .

14 ) enthalpy change is nothing but heat absorbed or evolved .

During fusion enthalpy change

Δ H .= m Lf , m is mass and Ls is latent heat of fusion

During evaporation, enthalpy change

Δ H .= m Lv , m is mass and Lv is latent heat of evaporation

during temperature rise , enthalpy  change

Δ H = m c Δ T

In case of gas , enthalpy change can be calculated by the following relation

Δ H = Δ E + W , Δ E is change in internal energy , W is work done by gas.

15 ) When enthalpy change is negative , that means heat is released to the environment .So reaction is called exothermic .

when heat is absorbed enthalpy change is positive . Reaction is endothermic.

5 0
3 years ago
The basic building blocks of proteins are:<br> O amino acids<br> O aldehydes<br> O amides<br> ODNA
Sonja [21]
Amino acids are the basic parts of proteins
8 0
3 years ago
Read 2 more answers
Can someone help me with number 1 and 2 plz!
GalinKa [24]

Answer:

1) 0 N

2) 8 N

Explanation:

The net force is the sum of all of the forces acting on the object.

For question 1, we can see that there is a force of 5 N acting to the right and 5 N acting to the left.  If we define the right to be positive and the left to be negative, then the net force equals:

Fnet = 5N - 5N = 0 N

Therefore, the net force in question 1 is 0 N.

For question 2, the process is very similar.  We want to find the sum of the forces acting on the object.  In this case, there are forces of 3 N and 5 N acting to the right.

Fnet = 3 N + 5 N = 8 N

Therefore, the net force in question 2 is 8 N.

Hope this helps!

3 0
3 years ago
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