[ Q ] = [ Delta U ] + [ W sub B ]
No work is done. -----> [ W sub B ] = 0.0
[ Delta U ] = [ m ] [ C sub V ] [ T2 - T1 ]
[ Delta U ] = [ 50 ] [ 0.58 ][70 - 20 ]
[ Delta U ] = 58 cal
Q = [ Delta U ] = 58cal
A. ) Chemical
B.) Mechanical
C.) Thermal
D.) Potential
Hope this helps!
Mass of iron(III)oxide, Fe2O3 sample = 1.143*10^2 g
Molar mass of Fe2O3 = 159.69 g/mole
i.e. 1 mole of Fe2O3 weighs 159.69 g
Based on stoichiometry:
1 mole of Fe2O3 has 2 moles of Fe
Atomic mass of Fe = 55.85 g/mole
Therefore we can write:
159.69 g of Fe2O3 is composed of 2*55.85 g of Fe
Thus, amount of Fe present in 1.143*10^2 g sample of Fe2O3 is
= 1.143*10^2 * 2* 55.85/159.69
= 7.995*10^-1 g
Only C. a temperature probe sends its measurement directly to a computer.
However, you can buy stopwatches that send their measurements via Bluetooth to your smartphone and you can then download them to a computer.
Answer:
The ionization energy (in kJ/mol) of the helium ion is 21,004.73 kJ/mol .
Explanation:
Z = atomic mass
n = principal quantum number
Energy of the electron in n=1,
Energy of the electron in n = ∞
Ionization energy of the 
ion:
To convert in into kj/mol multiply it with 
