Answer:
The reaction will be slower because the leaving group will be poorer.
Explanation:
One Important thing to put at the back of our mind is that weak bases are good leaving groups. Another thing to take note is that in the halogen series(which is our main subject in this question) as you go down the group the greater or the more heavy the halide is and the heavier halides are more stable that is Bromine will be more stable than chlorine.
Now, we are now told that the bromo halide is been replaced by the chloro halide which means that the rate of Reaction will surely decrease because the leaving group. The cl^- is a stronger base.
No because the mass of the empty beaker , mass of beaker is not balanced the amount of alcohol in the beaker.
The OH peaks in the IR spectra of benzyl alcohol and benzoic acid should be compared and contrasted.
<h3>What is the IR spectra of Benzoic acid?</h3>
- The right-hand portion of the infrared spectrum of benzoic acid, between wavenumbers 1500 and 400 cm-1, is referred to as the fingerprint region.
- It results from a special combination of intricately overlapping vibrations of the atoms within the benzoic acid molecule.
<h3>What is the IR spectra of Benzyl alcohol?</h3>
- A C-Cl bond is frequently shown by a peak at 700.
- There are a few more peaks at 1500 that are directed at a C=C bond.
<h3>What is IR spectra?</h3>
The percent transmittance (or absorbance) of the radiation through the molecule against the radiation's wave number forms the IR spectrum.
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The material which requires the most heat to raise its temperature from 10°C to 30°C is oil.
<h3>What is the formula to calculate absorbed heat?</h3>
The formula which we used to calculate the amount of involved heat in relation with specific heat is:
Q = mcΔT, where
- Q = absorbed heat
- m = mass
- c = specific heat
- ΔT = change in temperature
Among the given materials, specific heat of oil is highest than other materials so will require maximum absorbed heat.
Hence, oil requires the most heat.
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Answer:
i believe it is titanium.
Explanation: