The 5 rotational levels would there be between the ground vibrational state and the first excited vibrational state.
What is rotational levels?
The three major moments of inertia IA, IB, and IC determine the rotational energy levels for a nonlinear molecule. They revolve around three axes that are mutually orthogonal to one another and have their origin (or intersection) at the molecule's Centre of mass.
What is vibrational state?
The rotation of the molecule brought on by various vibrations in perpendicular planes is described by (123) or (12l23), where 0 l2 2 is an angular momentum quantum number.
Therefore , 5 rotational levels would there be between the ground vibrational state and the first excited vibrational state.
Learn more about rotational levels from the given link.
brainly.com/question/22283462
#SPJ4
Answer: True
Explanation: To be honest, I guessed. But, it looks right to me. If you don't trust it, you should wait for someone else to answer. Sorry! :(
Answer:
<h2>91.2</h2>
Explanation:
Given that:
Temperature = 60 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (60 + 273.15) K = 333.15 K
n = 5.14 × 10⁻³ mol
V = 1,171 mL = 1.171 L ( 1 mL = 0.001 L)
Using ideal gas equation as:

where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 62.364 L Torr/ K mol
Applying the equation as:
P × 1.171 L = 5.14 × 10⁻³ mol × 62.364 L Torr/ K mol × 333.15 K
<u>⇒P = 91.2 torr</u>
Answer:
b the amount of product measured after a reaction
Explanation:
good luck
Answer:
HCl < CH₃COOH < NH₃ < NaOH
Explanation:
Given compounds:
Acetic acid: CH₃COOH
Ammonia; NH₃
Hydrochloric acid: HCl
Sodium hydroxide: NaOH
All the solutions are of the same molarity which is 0.1M. We need to see how these compounds dissociate to form solutions in order to establish their pH value:
For Acetic acid;
CH₃COOH + H₂O ⇄ H₃O⁺ + CH₃COO⁻
Acetic acid is a weak acid and it ionizes slightly in solutions. It would have a pH close to 7
For Ammonia;
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
Ammonia is a weak base and it ionizes slightly in solutions. It sets up an equilibrium in the process. It's would be slightly above 7
For HCl:
HCl + H₂O → H₃O⁺ + Cl⁻
HCl is a strong acid and ionizes completely in solutions. It has a very low pH
For NaOH:
NaOH → Na⁺ + OH⁻
NaOH ionizes also completely in solutions and it breaks down into sodium and hydroxide ions. It is a strong base and it would have a high PH value.
HCl < CH₃COOH < NH₃ < NaOH
This is the trend of increasing pH