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djverab [1.8K]
3 years ago
14

Select each correct answer.

Mathematics
1 answer:
egoroff_w [7]3 years ago
3 0
A) reflect graph over x-axis (minus in front)
e) compress the graph to the x-axis (coefficient 1/2)
f) translate the graph to the right (x-9), minus between x and 9.
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What is the greatest number of obtuse angles a triangle can contain?
NikAS [45]
I think 1 because if you had 2 you'll end up with a shape that is greater than 180 degrees. Keep in mind obtuse angles a over 90 degrees. hope that helped
5 0
3 years ago
Read 2 more answers
Can someone help me pls
FrozenT [24]
There are 4 lateral faces that are triangles.  Each triangle is: A = \frac{b  x  h}{2}
A = \frac{16  x  22}{2}
   = 176

There is one base that is a square. A = L x W
A = 16 x 16
   =  256

Surface area = 256 + 4(176)
                     =  256 + 704
                     = 960

Answer: B

8 0
3 years ago
Read 2 more answers
A random experiment was conducted where a Person A tossed five coins and recorded the number of ""heads"". Person B rolled two d
cestrela7 [59]

Answer:

(10) Person B

(11) Person B

(12) P(5\ or\ 6) = 60\%

(13) Person B

Step-by-step explanation:

Given

Person A \to 5 coins (records the outcome of Heads)

Person \to Rolls 2 dice (recorded the larger number)

Person A

First, we list out the sample space of roll of 5 coins (It is too long, so I added it as an attachment)

Next, we list out all number of heads in each roll (sorted)

Head = \{5,4,4,4,4,4,3,3,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,0\}

n(Head) = 32

Person B

First, we list out the sample space of toss of 2 coins (It is too long, so I added it as an attachment)

Next, we list out the highest in each toss (sorted)

Dice = \{2,2,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6\}

n(Dice) = 30

Question 10: Who is likely to get number 5

From person A list of outcomes, the proportion of 5 is:

Pr(5) = \frac{n(5)}{n(Head)}

Pr(5) = \frac{1}{32}

Pr(5) = 0.03125

From person B list of outcomes, the proportion of 5 is:

Pr(5) = \frac{n(5)}{n(Dice)}

Pr(5) = \frac{8}{30}

Pr(5) = 0.267

<em>From the above calculations: </em>0.267 > 0.03125<em> Hence, person B is more likely to get 5</em>

Question 11: Person with Higher median

For person A

Median = \frac{n(Head) + 1}{2}th

Median = \frac{32 + 1}{2}th

Median = \frac{33}{2}th

Median = 16.5th

This means that the median is the mean of the 16th and the 17th item

So,

Median = \frac{3+2}{2}

Median = \frac{5}{2}

Median = 2.5

For person B

Median = \frac{n(Dice) + 1}{2}th

Median = \frac{30 + 1}{2}th

Median = \frac{31}{2}th

Median = 15.5th

This means that the median is the mean of the 15th and the 16th item. So,

Median = \frac{5+5}{2}

Median = \frac{10}{2}

Median = 5

<em>Person B has a greater median of 5</em>

Question 12: Probability that B gets 5 or 6

This is calculated as:

P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}

From the sample space of person B, we have:

n(5\ or\ 6) =n(5) + n(6)

n(5\ or\ 6) =8+10

n(5\ or\ 6) = 18

So, we have:

P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}

P(5\ or\ 6) = \frac{18}{30}

P(5\ or\ 6) = 0.60

P(5\ or\ 6) = 60\%

Question 13: Person with higher probability of 3 or more

Person A

n(3\ or\ more) = 16

So:

P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Head)}

P(3\ or\ more) = \frac{16}{32}

P(3\ or\ more) = 0.50

P(3\ or\ more) = 50\%

Person B

n(3\ or\ more) = 28

So:

P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Dice)}

P(3\ or\ more) = \frac{28}{30}

P(3\ or\ more) = 0.933

P(3\ or\ more) = 93.3\%

By comparison:

93.3\% > 50\%

Hence, person B has a higher probability of 3 or more

7 0
3 years ago
(-3x + 7) + (-6x + 9) =<br> pls help :)
babymother [125]

Answer:

-9x+16

Step-by-step explanation:

-3x+7+-6x+9=-9x+16

-3-6= (tecnectly adding but put negative sign with ur answer!)

7+9=16

Put together and Done!

Hope helps :D

4 0
3 years ago
Xander is taking a 5 question quiz worth 100 points. Each question is worth 20 points. Write an equation in function notation th
pashok25 [27]
Add 100 +20 - 5 and the total is the resort
6 0
3 years ago
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