All categories

3 years ago

Select each correct answer.

Mathematics

1 answer:

egoroff_w [7]3 years ago

3 0

A) reflect graph over x-axis (minus in front)
e) compress the graph to the x-axis (coefficient 1/2)
f) translate the graph to the right (x-9), minus between x and 9.

You might be interested in

Lane went to the bookstore he spent 1/3 of his money on a pen and 4/6 of it on books what fraction of his money did he have left

Mumz [18]

Answer: I believe that it might be $1.00

Step-by-step explanation: Well the problem doesn’t tell you how much money he HAD, so if you do 1/3+4/6 you should get 6/6 or 1 as the amount that Lane had.

3 0

3 years ago

Read 2 more answers

(-0.42,0.91)

Brilliant_brown [7]

Answer:

$\cos(\pi -\theta) = 0.42$

$\cos(2\pi +\theta) = -0.42$

3 0

3 years ago

the nutrition facts label from a 12 oz can of soft drink is shown below. Note that a serving of the soft drink is defined as 8 o

Nataliya [291]

The correct answer is C. 65

Explanation:

The serving size of the soft drink is 8oz, besides this, the amount of sugar for this serving size according to the label is 26 grames. Now, to calculate the amount of sugar in 20oz, one of the simplest methods is to use a rule of three, because three values are known, and one is missing. The process is shown below:

1. Write the known values and use x to represent the unknown values

8 oz = 26 grames of sugar

20 oz = x

2. Use cross multiplication (this means multiply 8 x 6) and divide it into the remaining value

$x = \frac{26 x 20}{ 8}$ or x = 26 x 20 / 8

3. Solve the equation

$x =\frac{520}{8}$ or x = 520 / 8

$x = 65$

4 0

3 years ago

Can y’all answer the question for me please

zepelin [54]

Answer:

Step-by-step explanation:

Jndjd

Njxjdh

Ndjdjjf

Mjd

6 0

3 years ago

Read 2 more answers

Differentiate. F(x) = (x3 - 3)2/3 2x f'(x) - 3 8 O f'(x) = 3 8 2x2 f'(x) 3 VX3 -8 f(x) 3 V3-8

oee [108]

Answer:

$f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } }$

Step-by-step explanation:

$f(x) = ( {x}^{3} - 8)^{ \frac{2}{3} } \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2} - 0) \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2 - 3}{3} } \times 3 {x}^{2} \\ \\ f'(x) = 2{x}^{2}( {x}^{3} - 8)^{ \frac{ - 1}{3} } \\ \\ f'(x) = \frac{2{x}^{2}}{( {x}^{3} - 8)^{ \frac{ 1}{3} } } \\ \\ \huge \red{ \boxed{ f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } } }}$

3 0

3 years ago