If 21 mL of gas is subjected to a temperature change from 10.0°C to 120°C and a pressure change from 1.0 atm to 15 atm, the new
volume is: (Be sure to use the correct number of significant figures.) 1.9 mL 1.0 mL 0.53 mL 440 mL
1 answer:
The new volume is 1.9 ml
<u><em> calculation</em></u>
The new volume is calculated using the combined gas equation
that is P1V1/T1 = P2V2/T2 where
P1= 1.0 atm
V1= 21 ml
T1 = 10.0 c into kelvin = 10 + 273 = 283 k
P2 = 15 atm
V2=? Ml
T2 = 120 c into kelvin = 120 +273 = 393 K
make V2 the subject of the formula by multiplying both side by T2/P2
V2=T2P1v1 / P2T1
V2=[(393 k x 1.0 atm x 21 ml) / (15 atm x 283 K)] = 1.9 Ml
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