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storchak [24]
3 years ago
14

A tortoise walks 3 inches in 1 second. How many feet per second can the tortoise walk?

Mathematics
2 answers:
vampirchik [111]3 years ago
5 0

Answer:

To answer the question, you need to write a conversion factor to convert inches to feet.

The correct conversion factor has the inches in the denominator.

The correct conversion factor has the feet in the numerator.

The tortoise can walk  0.25 feet per second.

Step-by-step explanation:

just took quiz

den301095 [7]3 years ago
4 0
Set up the conversion factor like this:

\frac{3in}{1} * \frac{1ft}{12in}

The inches are in the denominator while the feet are in the numerator in the conversion factor.  It's set up this way because the numerators and denominators have to be able to cancel out.  In this case, the inches would cancel out, and you would end up with 3/12 feet, which is also 0.25 feet.  The turtle walks 0.25 feet per second.
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The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

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therefore

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step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have

DE=7\ units

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substitute

A=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

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Step-by-step explanation:

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