Answer:
I guess the answer is charging by friction
Answer:
Rt = 908.25 [ohm]
Explanation:
In order to solve this problem, we must remember that the resistors connected in series are added up arithmetically.
In this case, R2 and R3 are in series therefore.
R₂₃ = 200 + 470
R₂₃ = 670 [ohm]
Now this new resistor (R₂₃) is connected in parallel with the resistor R4. therefore we must use the following arithmetic expression, to add resistances in parallel.
![\frac{1}{R_{4-23} }= \frac{1}{R_{4}}+\frac{1}{R_{23} } \\\frac{1}{R_{4-23} }=\frac{1}{1800}+\frac{1}{670} \\R_{4-23}=488.25[ohm]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR_%7B4-23%7D%20%7D%3D%20%5Cfrac%7B1%7D%7BR_%7B4%7D%7D%2B%5Cfrac%7B1%7D%7BR_%7B23%7D%20%7D%20%20%20%5C%5C%5Cfrac%7B1%7D%7BR_%7B4-23%7D%20%7D%3D%5Cfrac%7B1%7D%7B1800%7D%2B%5Cfrac%7B1%7D%7B670%7D%20%20%5C%5CR_%7B4-23%7D%3D488.25%5Bohm%5D)
In this way R₁, R₅ and R₄₋₂₃ are connected in series.
Rt = R₁ + R₅ + R₄₋₂₃
Rt = 150 + 270 + 488.25
Rt = 908.25 [ohm]
The answer is c hope it helps
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Actually Welcome to the Concept of the Kinematics in real world.
So, as given here, we have to find the Mass of the bus from the given momentum, so we get as,
P = m * V
momentum = mass * velocity
here, P= 152625 kgm/s and v= 11.1 m/s
so substituting we get as,
m = 152625 ÷ 11.1 => 13,750 kg
hence,the mass of the bus is 13,750 kg.