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3 years ago

What is the total current for the circuit? (must include unit - A) I WILL GIVE BRAINLIEST!

Physics

1 answer:

Iteru [2.4K]3 years ago

3 0

Answer:2 amperes

Explanation:

Voltage=120v

Total resistance=15+15+30

Total resistance=60 ohms

Current=voltage ➗ resistance

Current=120 ➗ 60

Current=2 amperes

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☆ Correct and rewrite the following statements:

il63 [147K]

Answer:

<h3>a) </h3><h3>Question:-</h3>

Rubber is a good conductor of electricity.

<h3>Answer:-</h3>

It's incorrect sentence.
As we know that, rubber are an insulators of electricity, and they do not not have free ions which can help in conducting electricity.

So correct sentence is:

Rubber is a bad conductor of electricity.

<h3>b)</h3><h3>Question:-</h3>

Electroplating wastes are useful to human health and environment.

<h3>Answer:-</h3>

It's incorrect sentence. 
As we know that, electroplating of substances releases harmful and toxic substances into the environment causing serious health issues in human, so it's waste substances released into environment can have very harmful effects.

So correct sentence is:

Electroplating wastes are harmful to human health and environment.

<h3>c)</h3><h3>Question:-</h3>

In an LED bulb, the shorter lead is connected to the positive terminal of the battery.

<h3>Answer:-</h3>

It's incorrect sentence. 
As we know that, in an LED bulb their are two terminals that is the positive and the negative. So here the lead connected to the positive terminal is always slightly longer than the lead connected to negative terminal of the bulb.

So correct sentence is:

In an LED bulb, the longer lead is connected to the positive terminal of the battery.

<h3>d)</h3><h3>Question:-</h3>

Pure water conducts electricity.

<h3>Answer:-</h3>

It's incorrect sentence. 
As we know that, pure water is a form of H2O where Hydrogen (H) is positive ion and Oxygen (O) is a negative ion which can conduct electricity when they are in individuals but as in pure water they are in combined form of compound H2O in which they become neutral and can't conduct any electricity.

So correct sentence is:

Pure water can't conduct electricity.

3 0

2 years ago

A 60 kg skydiver is falling at a terminal velocity of 50 m/s.

marishachu [46]

Answer:

The gravitational force is definitely acting downwards towards the ground and this is equal to the weight of the skydiver.

the acceleration a = 7.8 m/s²

Explanation:

Given that :

the mass of the skydiver = 60 kg

Velocity = 50 m/s

Thus; gravitational force is definitely acting downwards towards the ground and this is equal to the weight of the skydiver.

Also; the air resistance is acting upward and the resultant of both forces = mass×acceleration

So;

mg-R = ma

60(9.8) - 120 = 60(a)

588 -120 = 60a

468 = 60a

a = $\frac{468}{60}$

a = 7.8 m/s²

Hence, the acceleration a = 7.8 m/s²

5 0

3 years ago

happy valentines everyone <3 I dont want a partner i just want a crumb of future PLEASE "A steel bridge is 1000 m long at -20

pickupchik [31]

Answer:

1000.66m

Explanation:

$l 2 = l1(1 + \alpha \: \times change \:in \: temperature)$

L1=1000m

Temperature 1=-20

L2=?

Temperature 2=40

Temperature difference=40-(-20)

40+20=60

inserting into the formula

l2=l1(1+α×changeintemperature)

L2=1000(1+11×10^-6 ×60)

L2=1000(1+6.6×10^-4)

L2=1000(1.000.66)

L2=1000.66m

8 0

3 years ago

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Someone help pleaseeee

SSSSS [86.1K]

Answer:

C. resonating

an object being forced to vibrate at its natural frequency creates resonance

5 0

3 years ago

A 1.90-m-long barbell has a 25.0 kg weight on its left end and a 37.0 kg weight on its right end. if you ignore the weight of th

gregori [183]

Answer: The center of gravity is 1.1338 m away from the left side of the barbell

Explanation:

Length of the barbell = 1.90 m

The distance center of gravity from left = x

Mass on the left side = 25 kg

The distance center of gravity from right = 1.90 - x

Mass on the right side = 37 kg

At the balance point: $m_1x_1=m_2x_2$

$25 kg\times x=37 kg\times (1.90-x)$

$x=1.1338 m$

The center of gravity is 1.1338 m away from the left side of the barbell

7 0

3 years ago

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