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VMariaS [17]
4 years ago
9

The system of equations is coincident.

Mathematics
1 answer:
spin [16.1K]4 years ago
4 0
The equation is
-6x+15y=36, and you get the answer by multiplying the first equation by 3<span />
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Help please
tester [92]

Answer:

64y² - 81

Step-by-step explanation:

(8y +9)(8y - 9)

64y² - 72y + 72y - 81

64y² - 81

6 0
3 years ago
Read 2 more answers
The weight of animal hearts can range widely. An African bull elephant's heart can weigh as much as 61.73 pounds. A blue whale's
Bogdan [553]
The difference between a blue whale's heart and a African bull elephant heart is 2963.27 lbs. it will take 49 African bull elephant's heart to equal one blue whale's heart.
4 0
3 years ago
Read 2 more answers
A researcher is interested in estimating the mean weight of a semi trailer truck to determine the potential load capacity. She t
Kaylis [27]

Answer: 95% confidence interval = 20,000 ± 2.12\times\frac{1500}{\sqrt{17} }

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

Step-by-step explanation:

Given :

Sample size(n) = 17

Sample mean = 20000

Sample standard deviation = 1,500

5% confidence

∴ \frac{\alpha}{2} = 0.025

Degree of freedom (d_{f}) = n-1 = 16

∵ Critical value at ( 0.025 , 16 ) = 2.12

∴ 95% confidence interval = mean ± Z_{c}\times\frac{\sigma}{\sqrt{n} }

Critical value  at 95% confidence interval = 20,000 ± 2.12\times\frac{1500}{\sqrt{17} }

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

3 0
4 years ago
X^2+y^2+14x+10y=7 <br> center and radius
Sholpan [36]
(x-a)^2+(y-b)^2=r^2\\\\(a;\ b)-the\ coordinates\ of\ the\ center\\r-the\ radius\\\\==================================\\Use:(k+l)^2=k^2+2kl+l^2\ (*)\\==================================

x^2+y^2+14x+10y=7\\\\x^2+14x+y^2+10y=7\\\\x^2+2x\cdot7+y^2+2y\cdot5=7\\\\\underbrace{x^2+2x\cdot7+7^2}_{Use\ (*)}-7^2+\underbrace{y^2+2y\cdot5+5^2}_{Use\ (*)}-5^2=7\\\\(x+7)^2-49+(y+5)^2-25=7\\\\(x+7)^2+(y+5)^2-74=7\ \ \ \ |add\ 74\ to\both\ sides\\\\(x+7)^2+(y+5)^2=81\\\\(x+7)^2+(y+5)^2=9^2

Answer:\\\boxed{(-7;-5)-center;\ 9-radius}
8 0
3 years ago
Read 2 more answers
The radius of one circle is three the time radius of another circle. The sum of their areas is 12pi. Find the radius of each cir
zlopas [31]
   
\displaystyle\\&#10;\begin{cases}&#10;R_1 = 3R_2\\&#10;\pi R_1^2 +\pi R_2^2=12\pi ~~~\Big|~~:\pi &#10;\end{cases} \\  \\ &#10;\begin{cases} &#10;R_1 = 3R_2\\&#10;R_1^2 + R_2^2=12 &#10;\end{cases} \\  \\ &#10;(3R_2)^2+ R_2^2=12 \\  \\ &#10;9R_2^2 + R_2^2=12 \\  \\ &#10;10R_2^2=12\\\\&#10;R_2^2 = \frac{12}{10} = \frac{6}{5}  \\  \\ &#10;R_2 =  \boxed{\sqrt{\frac{6}{5}} } \\  \\ &#10;R_1 = \boxed{3\sqrt{\frac{6}{5}} }



7 0
3 years ago
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