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Lady bird [3.3K]
3 years ago
6

Researchers have now been able to cool substances to absolute zero. a. True b. False

Chemistry
2 answers:
harina [27]3 years ago
5 0

Answer:

The correct option is B) false.

Explanation:

Absolute zero is the point where it is not feasible to cool further.

The lowest possible temperature is 0 kelvin which is also known as absolute zero. In degrees its corresponds to –273.15 degrees Celsius.

it is not possible to reach or cool a substance to absolute zero although nearby temperatures can be reached.

Consider the provided statement.

Researchers have now been able to cool substances to absolute zero is a false statement.

The correct option is B) false.

katovenus [111]3 years ago
3 0
This Answer Is False.

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The crystalline allotropes of sulfur are very strong and have a high melting and boiling point while the amorphous allotropes of sulfur are brittle and breaks easily.

<h3>What is a crystalline substance?</h3>

A crystalline substance is one that has a definite arrangement of the atoms in the substance. An amorphous substance lacks this definite arrangement. We can see this arrangement when we conduct an X-ray crystallography of the sulfur.

Also, the crystalline allotropes of sulfur are very strong and have a high melting and boiling point while the amorphous allotropes of sulfur are brittle and breaks easily.

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1 year ago
While mercury is very useful in barometers, mercury vapor is toxic. Given that mercury has a ΔHvap of 59.11 kJ/mol and its norma
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2.38×10^-3

Explanation:

from the question,the we calculate the latent heat of vaporization with the difference in temperature being put into consideration

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2 years ago
The experiment where the factors being tested are not applied. It allows scientists to set a baseline to compare the experimenta
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3 years ago
Standard 1.11<br> The blue and red parts of the atoms represent the?
andrey2020 [161]
The number of protons in the nucleus for that element
8 0
3 years ago
The average lung capacity of a human is 6.0L.
Darya [45]

Answer:

(a) 0.25 mol

(b) 0.11 mol

(c) 8.77 mol

Explanation:

(a)

We use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 298 K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

1.00 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1.00\times 6.0}{0.0821\times 298}=0.25mol

(b)

We use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 0.296 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 200 K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

0.296 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 200K\\\\n=\frac{0.296\times 6.0}{0.0821\times 200}=0.11mol

(c)

We use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 30 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 250 K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

30 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 250K\\\\n=\frac{30\times 6.0}{0.0821\times 250}=8.77mol

8 0
3 years ago
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