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leva [86]
2 years ago
15

It is defined as the number of particles per mole of a substance. *

Chemistry
1 answer:
luda_lava [24]2 years ago
7 0

Answer:

Avogadro's number

Explanation:

Avogadro's number

defined as the number of elementary particles (molecules, atoms, compounds, etc.) per mole of a substance. It is equal to 6.022×1023 mol-1 and is expressed as the symbol NA.

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Steel is the most commonly used metallic material. However, its annual loss due to corrosion is huge. Preventing metal corrosion
Fiesta28 [93]

Answer:

d

Explanation:

elvis's do fhgffgcgxcycy

5 0
2 years ago
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Is this an example of decomposition<br> 2CH4 + 402 → 2C02 + 4H2O
Molodets [167]

Answer:

Identify each equation as a composition reaction, a decomposition reaction, or neither.

Fe2O3 + 3 SO3 → Fe2(SO4)3

NaCl + AgNO3 → AgCl + NaNO3

(NH4)2Cr2O7 → Cr2O3 + 4 H2O + N2

Solution

In this equation, two substances combine to make a single substance. This is a composition reaction.

Two different substances react to make two new substances. This does not fit the definition of either a composition reaction or a decomposition reaction, so it is neither. In fact, you may recognize this as a double-replacement reaction.

A single substance reacts to make multiple substances. This is a decomposition reaction.

Test Yourself

Identify the equation as a composition reaction, a decomposition reaction, or neither.

C3H8 → C3H4 + 2 H2

Explanation:

I hope I help :)))

5 0
3 years ago
An inverted pyramid is being filled with water at a constant rate of 45 cubic centimeters per second. The pyramid, at the top, h
vaieri [72.5K]

Answer:

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

Explanation:

Length of the base = l

Width of the base  =  w

Height of the pyramid = h

Volume of the pyramid = V=\frac{1}{3}lwh

We have:

Rate at which water is filled in cube = \frac{dV}{dt}= 45 cm^3/s

Square based pyramid:

l = 6 cm, w = 6 cm, h = 13 cm

Volume of the square based pyramid = V

V=\frac{1}{3}\times l^2\times h

\frac{l}{h}=\frac{6}{13}

l=\frac{6h}{13}

V=\frac{1}{3}\times (\frac{6h}{13})^2\times h

V=\frac{12}{169}h^3

Differentiating V with respect to dt:

\frac{dV}{dt}=\frac{d(\frac{12}{169}h^3)}{dt}

\frac{dV}{dt}=3\times \frac{12}{169}h^2\times \frac{dh}{dt}

45 cm^3/s=3\times \frac{12}{169}h^2\times \frac{dh}{dt}

\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times h^2}

Putting, h = 4 cm

\frac{dh}{dt}=\frac{45 cm^3/s\times 169}{3\times 12\times (4 cm)^2}

=13.20 cm/s

13.20 cm/s is the rate at which the water level is rising when the water level is 4 cm.

3 0
3 years ago
The variable that is observed during an experiment is called what type of variable?
professor190 [17]
The one that is observed or measured in the experiment, and it is known as the dependent variable. 
8 0
3 years ago
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How many moles of S would I have if I had 11 grams? (Stoichiometry) HELP
zepelin [54]
<h3>Answer:</h3>

0.34 mol S

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

11 g S

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 11 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})
  2. Multiply/Divide:                  \displaystyle 0.343 \ mol \ S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

0.343 mol S ≈ 0.34 mol S

4 0
2 years ago
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