A 3.00 L flexible container holds a sample of hydrogen gas at 153 kPa. If the pressure increases to 203 kPa and the temperature
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Answer: D=4.35g/L
Explanation:
The formula for density is . M is mass in grams and V is volume in liters.
Since we are give pressure and temperature, we can use the ideal gas law to find moles/volume. FInding moles/volume would give us the base for density. All we would have to do is convert moles to grams.
Ideal Gas Law: PV=nRT
Now that we have moles, we can use molar mass of chlorine gas to find grams.
With our grams, we can find our density.
We need correct significant figures so our density is:
Answer:
4.993 ×10⁻¹¹ J
Explanation:
The <em>nuclear binding energy</em> is the energy equivalent to the mass defect.
The <em>mass defect</em> is the difference between the mass of a nucleus and the sum of the masses of its nucleons.
<em>Calculate the mass defect </em>
16 p = 16 × 1.007 28 u = 16.116 48 u
16 n = 16 × 1.008 67 u = 16.138 72 u
Total mass of nucleons = 32.255 20 u
- Mass of S-32 = <u>31.972 070 u </u>
Mass defect = 0.283 13 u
Convert the <em>unified atomic mass units to kilograms</em>.
Mass defect
Use Einstein’s equation to <em>convert the mass defect into energy</em>
Answer:
The given molecules are SO2 and BrF5.
Explanation:
Consider the molecule SO2:
The central atom is S.
The number of domains on S in this molecule is three.
Domain geometry is trigonal planar.
But there is a lone pair on the central atom.
So, according to VSEPR theory,
the molecular geometry becomes bent or V-shape.
Hybridization on the central atom is
.
Consider the molecule BrF5:
The central atom is Br.
The number of domains on the central atom is six.
Domain geometry is octahedral.
But the central atom has a lone pair of electrons.
So, the molecular geometry becomes square pyramidal.
The hybridization of the central atom is .
The shapes of SO2 and BrF5 are shown below:
