Answer:
First, we start with:
"Ram obtains 40% of the marks in a paper of 200 marks"
In this case, 200 marks represent the 100%
Then how much is the 40%?
we have the relations:
40% = X
100% = 200 marks
Now we can take the quotient of both equations:
(40%/100%) = X/200marks
(40%/100%)*200marks = X = 80 marks
So Ram obtained 80 marks.
Now we have:
"Shyam is ahead of Ram by 25% of Ram's marks"
Now the 100% is the number of marks that Ram has, this is:
100% = 80 marks
And Shyam has 25% more than that, then we have:
125% = X
Same as before, we take the quotient of both equations:
(125%/100%) = X/80 marks
1.25*80 marks = 100 marks.
Shyam has 100 marks.
The last part is (this is not written correctly, it says "one month", it should be "one-ninth")
"while Bhuvan is ahead of Shyam by one-ninth of his own marks."
if his own marks are X, we have the equation
X = 100 + (1/9)*X
X - 1/9*X = 100
X*(8/9) = 100
X = (9/8)*100 = 112.5
So Bhuvan has 112.5 marks
= 0