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pochemuha
3 years ago
10

a car climbs 10.0 kilometers up a hill that inclines 8.0 degrees. what is the car's vertical displacement.

Physics
1 answer:
lakkis [162]3 years ago
4 0
Ok so the answer will be 1.39km. 

First use SOH-CAH-TOA

Sine (SOH)=Opp/Hyp

Sin (8°) = vertical height/hypotenuse
Hypotenuse = 10 km
Vertical height =?
vertical height = sin (8°) × 10km = 1.39 Km


I hope this helps. :3
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The force of attraction between a ball is F=.........×10^-¹¹
DIA [1.3K]

Answer:

4.45×10¯¹¹ N

Explanation:

From the question given above, the following data were obtained:

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The force of attraction between the ball and the bowling pin can be obtained as follow:

F = GM₁M₂ / r²

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F = 4.002×10¯¹⁰ / 9

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8 0
3 years ago
One of the harmonics on a string 1.30m long has a frequency of 15.60 Hz. The next higher harmonic has a frequency of 23.40 Hz. F
Alja [10]

Answer:

\large \boxed{\text{(a) 7.800 Hz; (b) 20.3 m/s; 40.6 m/s; 60.8 m/s}}

Explanation:

a) Fundamental frequency

A harmonic is an integral multiple of the fundamental frequency.

\dfrac{\text{23.40 Hz}}{\text{15.60 Hz}} = \dfrac{1.500}{1} \approx \dfrac{3}{2}

f = \dfrac{\text{24.30 Hz}}{3} = \textbf{7.800 Hz}

b) Wave speed

(i) Calculate the wavelength

In a  fundamental vibration, the length of the string is half the wavelength.

\begin{array}{rcl}L & = & \dfrac{\lambda}{2}\\\\\text{1.30 m} & = & \dfrac{\lambda}{2}\\\\\lambda & = & \text{2.60 m}\\\end{array}

(b) Calculate the speed s

\begin{array}{rcl}v_{1}& = & f_{1}\lambda\\& = & \text{7.800 s}^{-1} \times \text{2.60 m}\\& = & \textbf{20.3 m/s}\\\end{array}

\begin{array}{rcl}v_{2}& = & f_{2}\lambda\\& = & \text{15.60 s}^{-1} \times \text{2.60 m}\\& = & \textbf{40.6 m/s}\\\end{array}

\begin{array}{rcl}v_{3}& = & f_{3}\lambda\\& = & \text{23.40 s}^{-1} \times \text{2.60 m}\\& = & \textbf{60.8 m/s}\\\end{array}

4 0
3 years ago
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