Answer:
88.89 cm/s or 0.89 m/s.
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0 cm/s
Distance travelled (s) = 120 cm
Time (t) = 2.7 s
Final velocity (v) =.?
The final velocity of the marble can be obtained as follow:
s = ½(v + u)t
120 = ½ × (v + 0) × 2.7
120 = (v + 0) × 1.35
120 = 1.35v + 0
120 = 1.35v
Divide both side by 1.35
v = 120/1.35
v = 88.89 cm/s
We may want to express the velocity in m/s. This can be obtained as follow:
100 cm/s = 1 m/s
Therefore,
88.89 cm/s = 88.89 cm/s × 1 m/s /100 cm/s
88.89 cm/s = 0.8889 m/s
88.89 cm/s = 0.89 m/s
Thus, the marble's final velocity is 88.89 cm/s or 0.89 m/s
Explanation:
Taking the incident light to be traveling in the + x-direction so that it is at normal incidence to the left side of the film(referred to as the "Front side"). This means the beam transmitted into the liquid is essentially as strong as the incident beam.
Almost all the light that is reflected off the back surface will get through the front surface. (But only 2.78% gets re-reflected off the the front surface back to the right) this means that there are two beams reflected to the - x-direction, one from the front surface and one from the back, and these beams are of almost equal intensity.
Hope this is helpful. Thanks
Answer: 68.4 s
Explanation:
The plot points seem to indicate a 5 m/s increase in velocity in the 6 seconds between 2 and 8 second marks. This makes the acceleration
a = 5 / 6 m/s/s
At time zero, the velocity is 13 m/s, so we need to increase by
70 - 13 = 57 m/s
t = v/a = 57 / (5/6) = 68.4 s
Answer:
The position, speed, direction and acceleration