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Allushta [10]
3 years ago
10

The diameter of Mars is 6794km, and its minimum distance from the earth is 5.58×10^7 km. When Mars is at this distance, find the

diameter of the image of Mars formed by a spherical, concave, telescope mirror with a focal length of 1.95 m .
Physics
1 answer:
pav-90 [236]3 years ago
4 0

Answer:

D = 0.2374 m

Explanation:

let D be the diameter of the image of mars, f be the focal length of the telescope mirror and β be the spatial resolution.

β = 6794×10^3/(5.58×10^7) = 0.1217562724

then:

The diameter of the telescope mirror is given by:

D = f×β

   = (1.95)×(0.1217562724)

   = 0.2374 m

Therefore, the diameter of the image of mars is 0.2374 m.

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Explain the difference between the terms "rotation" and "revolution"
Novay_Z [31]

Answer:

Explanation:

"Rotation" refers to an object's spinning motion about its own axis. "Revolution" refers the object's orbital motion around another object. For example, Earth rotates on its own axis, producing the 24-hour day. Earth revolves about the Sun, producing the 365-day year.

3 0
2 years ago
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A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
Dafna11 [192]

Answer:

The correct answer is B)

Explanation:

When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel.  So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.

The formula for calculating the velocity of a point on the edge of the wheel is given as

V_{r} = 2π r / T

Where

π is Pi which mathematically is approximately 3.14159

T is period of time

Vr is Velocity of the point on the edge of the wheel

The answer is left in Meters/Seconds so we will work with our information as is given in the question.

Vr = (2 x 3.14159 x 1.94m)/2.26

Vr = 12.1893692/2.26

Vr = 5.39352619469

Which is approximately 5.39

Cheers!

7 0
2 years ago
a 1210 kg roller coaster car is moving 6.33 m/s. as it approaches the station, brakes slow it down to 2.38 m/s over a distance o
Stels [109]

Answer:

4960 N

Explanation:

First, find the acceleration.

Given:

v₀ = 6.33 m/s

v = 2.38 m/s

Δx = 4.20 m

Find: a

v² = v₀² + 2aΔx

(2.38 m/s)² = (6.33 m/s)² + 2a (4.20 m)

a = -4.10 m/s²

Next, find the force.

F = ma

F = (1210 kg) (-4.10 m/s²)

F = -4960 N

The magnitude of the force is 4960 N.

4 0
3 years ago
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d is at rest at the top of a 2 m high slope. The sled has a mass of 45 kg. The sled's potential energy is J?
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<span>D is at rest at the top of a 2 m high slope. The sled has a mass of 45 kg. The sled's potential energy is J?
</span>Answer: The sled's potential energy is 882 Joules
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How many neutrons are in an atom of carbon with a mass number of 13
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C is the answer to your question.

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