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3 years ago

In what do electromagnetic waves cause disturbances when they transfer

Physics

2 answers:

IrinaVladis [17]3 years ago

5 0

Both electric and magnetic fields

Makovka662 [10]3 years ago

5 0

Answer should be b
hope this helps

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Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter

alukav5142 [94]

Answer: 0.258

Explanation:

The resistance $R$ of a wire is calculated by the following formula:

$R=\rho\frac{l}{s}$ (1)

Where:

$\rho$ is the resistivity of the material the wire is made of. For aluminium is $\rho_{Al}=2.65(10)^{-8}m\Omega$ and for copper is $\rho_{Cu}=1.68(10)^{-8}m\Omega$

$l$ is the length of the wire, which in the case of aluminium is $l_{Al}=12m$ , and in the case of copper is $l_{Cu}=30m$

$s$ is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:

$s=\pi{(\frac{d}{2})}^{2}$ (2) Where $d$ is the diameter of the circumference.

For aluminium wire the diameter is $d_{Al}=2.5mm=0.0025m$ and for copper is $d_{Cu}=1.6mm=0.0016m$

So, in this problem we have two transversal areas:

For aluminium:

$s_{Al}=\pi{(\frac{d_{AL}}{2})}^{2}=\pi{(\frac{0.0025m}{2})}^{2}$

$s_{Al}=0.000004908m^{2}$ (3)

For copper:

$s_{Cu}=\pi{\frac{(d_{Cu}}{2})}^{2}=\pi{(\frac{0.0016m}{2})}^{2}$

$s_{Cu}=0.00000201m^{2}$ (4)

Now we have to calculate the resistance for each wire:

Aluminium wire:

$R_{Al}=2.65(10)^{-8}m\Omega\frac{12m}{0.000004908m^{2}}$ (5)

$R_{Al}=0.0647\Omega$ (6) Resistance of aluminium wire

Copper wire:

$R_{Cu}=1.68(10)^{-8}m\Omega\frac{30m}{0.00000201m^{2}}$ (6)

$R_{Cu}=0.250\Omega$ (7) Resistance of copper wire

At this point we are able to calculate the ratio of the resistance of both wires:

$Ratio=\frac{R_{Al}}{R_{Cu}}$ (8)

$\frac{R_{Al}}{R_{Cu}}=\frac{0.0647\Omega}{0.250\Omega}$ (9)

Finally:

$\frac{R_{Al}}{R_{Cu}}=0.258$ This is the ratio

3 0

4 years ago

Wire coils spinning between two magnets will produce …?

klemol [59]

Answer:

Explanation:

I don't know but its b

6 0

3 years ago

Read 2 more answers

A horse pulls on a carriage. By Newton's third law, the carriage pulls back on the horse with equal force. Why do the action and

Andrews [41]

Answer:

By Newton's third law the cart must then exert an equal and opposite force on the horse. ... If it doesn't accelerate, and it started it rest, it must remain at rest (by the definition of acceleration), and therefore no matter how hard the horse pulls, it can never move the cart

5 0

3 years ago

How to find final velocity and initial velocity and acceleration ? :(

Effectus [21]

Explanation:

Final velocity=Initial velocity+(acceleration×time)

4 ways to find initial velocity:

1) Initial velocity=Final velocity-(acceleration×time)

2) Initial velocity=(Distance/Time)-((acceleration×time)/2)

3) Initial velocity=√Final velocity-(2×(acceleration×distance))

4) Initial velocity=2(distance/time)-Final velocity

Total force = Mass×Acceleration

(F=ma)

3 0

3 years ago

What is the least value of an ammeter Is it 1. 0.1 2. 0.10 3. 0.2 4. 0.5

givi [52]

The least value varies depends on ammeter range. In the given question, ammeter range is not mentioned. So, the least value of an ammeter is 0.1 or 0.5 (depends on ammeter range).

Explanation:

The least value of an ammeter is the measure of the smallest number which can be observed in ammeter. So the least value will be varying depending upon its range. If we consider the range of ammeter is 30 A and the scale readings are 10 numbers, then the least value will be 30/10 = 3 A per scale.

So the least value is determined as $\frac{Range of ammeter}{No.of scales}$

So among the given options 0.1 is most suitable for an ammeter with range of 3 A with 30 divisions.

3 0

3 years ago