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nlexa [21]
3 years ago
15

In what do electromagnetic waves cause disturbances when they transfer

Physics
2 answers:
IrinaVladis [17]3 years ago
5 0
Both electric and magnetic fields
Makovka662 [10]3 years ago
5 0
Answer should be b
hope this helps
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A 4-kilogram cat is resting on top of a bookshelf that is 3 meters high. What is the cat’s gravitational potential energy relati
hichkok12 [17]
The answer is 117.6 J

The potential energy of the object is actually its stored energy:

<span>E = m · g · h
E - the potential energy of the object,
m - the mass of the object,
g - acceleration due to gravity,
h - the height of the object.

m = 4 kg
g = 9.8 m/s</span>²
h = 3 m

E = 4 * 9.8 * 3 = 117.6 J
4 0
3 years ago
An object is in circular motion. How will the object behave if the centripetal force is removed
stich3 [128]

The object will sail away in a straight line ... continuing in the same direction it was going when the centripetal force stopped.

3 0
3 years ago
The radioactive element polonium decays according to the law given below where Q0 is the initial amount and the time t is measur
kogti [31]

Answer:

1280 mg

Explanation:

Radioactive  decay is a phenomenon that occurs when a certain isotope of an element, said to be radioactive, decays, turning into a lighter nucleus and emitting radiation + energy in the process.

The radioactive decay of this isotope of polonium is described by the equation

Q(t)=Q_0 2^{-\frac{t}{140}}

where

Q(t) is the amount of polonium left after time t

Q_0 is the amount of polonium t time t = 0

140 is the half-life of the polonium, in days (it is the time it takes for the initial element to halve its amount)

IN this problem, we know that:

After t = 560 days, the amount of polonium left is Q(t)=80 mg. Therefore, we can re-arrange the equation, substituting t = 560 d, and solve for Q_0 to find the initial amount of polonium:

Q_0 = Q(t) \cdot 2^{\frac{t}{140}}=(80)\cdot 2^{\frac{560}{140}}=1280 mg

5 0
3 years ago
A small candle is 38 cm from a concave mirror having a radius of curvature of 24 cm. (a) what is the focal length of the mirror?
Finger [1]
For a concave mirror, the radius of curvature is twice the focal length of the mirror:
r=2f
where f, for a concave mirror, is taken to be positive.

Re-arranging the formula we get:
f= \frac{r}{2}
and since the radius of curvature of the mirror in the problem is 24 cm, the focal length is
f= \frac{24 cm}{2} = 12 cm

8 0
4 years ago
Pls pls help i am in 8th grade k12 How is the temperature affected (increased or decreased) when the iron block is placed in the
PtichkaEL [24]

Explanation:

the water temperature increase or decrease

6 0
2 years ago
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