(II) A 0.280-kg croquet ball makes an elastic head-on collision with a second ball initially at rest. The second ball moves off
with half the original speed of the first ball. (a) What is the mass of the second ball? (b) What fraction of the original kinetic energy ( KE/KE) gets transferred to the second ball?
1 answer:
You might be interested in
Answer:
The length of the stick is 0.28 m.
The time the stick take to move is 0.97 ns.
Explanation:
Given that,
Relative speed of stick v= 0.96 c
Speed of light
Proper length of stick = 1 m
We need to calculate the length of the stick
Using formula of length
Put the value into the formula
We need to calculate the time the stick take to move
Using formula of time
Put the value into the formula
Hence, The length of the stick is 0.28 m.
The time the stick take to move is 0.97 ns.