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Vilka [71]
3 years ago
11

A pressure cooker is a covered pot sealed everywhere except for a small circular opening in the top. A small weight placed over

this opening determines the pressure at which steam is released from the pot. Suppose that the radius of the opening is 0.491 mm and the weight is 0.763 N. Find the maximum pressure inside the pot.
Physics
1 answer:
katrin [286]3 years ago
3 0

Answer:

10^6 Pa

Explanation:

Radius of the opening, r = 0.491 mm = 0.491 x 10^-3 m

Force, F = 0.763 N

Pressure is defined as the thrust acting per unit area. Its SI unit is Pascal.

Pressure = force / Area

Area, A = πr² = 3.14 x 0.491 x 10^-3 x 0.491 x 10^-3 = 7.57 x 10^-7 m^2

Pressure

P = \frac{0.763}{7.57 \times 10^{-7}}

P = 1 x 10^6 Pascal

Thus, the pressure inside the pot is 10^6 Pa.

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Answer:

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Explanation:

Given:-

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Solution:-

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                                   qnet = t*(1.000002 - 1.00000) = 0.000002*t

- The Volt potential on the surface of the conducting sphere according to Coulomb's Law derived result is given by:

                                   V = k*qnet / r

Where,                        k = 8.99*10^9   ..... Coulomb's constant

                                   qnet = V*r / k

                                   t = 1000*0.1 / (8.99*10^9 * 0.000002)

                                   t = 5.56 ms

                                   

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Answer:

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