3 years ago

Solve for real t: -25=20t-5t^2

Physics

1 answer:

PolarNik [594]3 years ago

3 0

Answer should be t=−1 or t=5

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B. is the correct answer.

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0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t 0, the puck is moving to the right at 3.00 m/s.

balandron [24]

Answer: $(a)10.812\ m/s\ (b)\ 0.75\ m/s\ \text{left}$

Explanation:

Given

Mass of hockey puck $m=0.160\ kg$

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First a horizontal force of $25\ N$ is applied to the right for $0.05\ s$

acceleration associated with it is

$\Rightarrow a=\dfrac{25}{0.160}\\\\\Rightarrow a=156.5\ m/s^2$

Using equation of motion i.e.

$\Rightarrow v=u+at\\\Rightarrow v=3+156.25\times 0.05\\\Rightarrow v=3+7.812\\\Rightarrow v=10.812\ m/s$

(b) When a force of $12\ N$ is applied for 0.05s

Using equation of motion i.e.

$\Rightarrow v=3-\dfrac{12}{0.160}\times 0.05\\\\\Rightarrow v=3-75\times 0.05\\\Rightarrow v=3-3.75\\\Rightarrow v=-0.75\ m/s\\\Rightarrow v=0.75\ \text{towards left}$

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3 years ago

A creature moves at a speed of 7.86 furlongs/fortnight (not a very common unit of speed). If 1.0 furlong = 220 yards 1 fortnight

AVprozaik [17]

Answer:

2 0.00130719 m/s

Explanation:

Now we have

7.86 furlongs/fortnight

7.86 x 220 yards / fortnight

1729.2yards / fortnight

1647.8 yards / 14 days

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123.5 x 0.9144 meter / day

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Pushing down with hands on the blanket increases the normal force between the soil and the blanket and, therefore, increases the friction force. Nonetheless, the component of the gravity force parallel to the direction of the slide is higher than friction force and consequently, the acceleration decreases but never goes to zero.

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Anvisha [2.4K]

Hello,

Here is your answer:

The proper answer to this question is option A "puffin".

Your answer is A.

If you need anymore help feel free to ask me!

Hope this helps!

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