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ale4655 [162]
3 years ago
9

Solve for real t: -25=20t-5t^2

Physics
1 answer:
PolarNik [594]3 years ago
3 0
Answer should be <span>t=<span>−<span><span>1<span> or  </span></span>t</span></span></span>=<span>5</span>
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A basketball referee tosses the ball straight up for the starting tipoff. at what velocity must a basketball player leave the gr
sladkih [1.3K]
Mgh=mv²/2

v=√2gh=√2·9.8·1.25=4.95m/s
5 0
3 years ago
After the pendulum is dropped, determine the height at which the kinetic energy is equal to the potential energy.
Fofino [41]
0.5 m v² = m g h
⇅
h = 0.5 v²/g
4 0
3 years ago
As an airplane accelerates in level flight, what parameter must the pilot adjust to keep level and balance Lift = Weight?
Y_Kistochka [10]

Answer:

C. Angle of Attack.

Explanation:

The pilot must adjust the angle of attack parameter. The angle of attack of this plane to get to the desired lift coefficient.

And thus, we have

Lift = Weight

3 0
2 years ago
A. If a T-Rex runs 20 meters in 4 seconds, what is it’s average speed?
mariarad [96]

5m/s

100m

Explanation:

Average speed is sum of distance distance traveled in a given time by a body.

 Average speed= \frac{total distance covered}{time taken}

Distance = 20m

time = 4s

  Average speed = \frac{20}{4} = 5m/s

For the spaceship;

   Distance covered = speed x time

Speed = 50m/s

time = 2s

 Distance covered = 50 x 2 = 100m

learn more:

Average speed brainly.com/question/5063905

#learnwithBrainly

3 0
2 years ago
A 10.0 g bullet moving at 300m/s is fired into a 1.00 kg block at rest. The bullet emerges (the bullet does not get embedded in
chubhunter [2.5K]

Answer:

v' = 1.5 m/s

Explanation:

given,

mass of the bullet, m = 10 g

initial speed of the bullet, v = 300 m/s

final speed of the bullet after collision, v' = 300/2 = 150 m/s

Mass of the block, M = 1 Kg

initial speed of the block, u = 0 m/s

velocity of the block after collision, u' = ?

using conservation of momentum

 m v + Mu = m v' + M u'

 0.01 x 300 + 0 = 0.01 x 150 + 1 x v'

v' = 0.01 x 150

v' = 1.5 m/s

Speed of the block after collision is equal to v' = 1.5 m/s

5 0
3 years ago
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