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3 years ago

9

Solve for real t: -25=20t-5t^2

1 answer:

PolarNik [594]3 years ago

3 0

Answer should be <span>t=<span>−<span><span>1<span> or </span></span>t</span></span></span>=<span>5</span>

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Why is energy important to motion?

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Energy is the force that creates motion

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3 years ago

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The track of a roller coaster is shown below. At which point will the riders experience centripetal acceleration?

valentinak56 [21]

Centripetal acceleration is applied in circular motion. Y is the point on the track that most closely resembles a circular path for the roller coaster.

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2 years ago

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Mike's car, which weighs 1,000 kg, is out of gas. Mike is trying to push the car to a gas station, and he makes the car go 0.05

Maru [420]

Answer:

The answer to your question is: F = 50 N

Explanation:

Data

mass = 1000 kg

acceleration = 0.05m/s2

F = ?

Formula

F = m x a

Substitution

F = 1000 kg x 0.05 m/s2 = 50 kgm/s2 = 50 N

Mike is applying a force of 50 N to the car.

3 0

3 years ago

A car moving south speeds up from 10 m/s to 40 m/s in 15 seconds. What is the car's acceleration?

ElenaW [278]

Answer: $2m/s^{2}$

Explanation:

Assuming the car is moving only in one direction (to the South), its acceleration $a$ is given by the following formula, which expresses the variation of the velocity in time:

$a=\frac{\Delta V}{\Delta t}$ (1)

Where:

$\Delta V=V_{2}-V_{1}=40m/s-10m/s=30m/s$ is the variation in velocity

$\Delta t=t_{2}-t_{1}=15s-0s=15s$ is the variation in time

Rewritting (1) with the calculated values:

$a=\frac{30m/s}{15s}$ (2)

$a=2m/s^{2}$ This is the acceleration of the car

7 0

3 years ago

A ball is swung in a horizontal circle at a constant speed. Each circle takes 0.85 seconds to complete and the rope is 0.40 m lo

BaLLatris [955]

Answer:

The centripetal acceleration will be "21.785 m/s²".

Explanation:

The given values are:

Time,

t = 0.85 seconds

Length of rope,

r = 0.40 m

Mass of ball,

m = 0.80 kg

As we know,

⇒ $w=\frac{2 \pi}{t}$

On substituting the values, we get

⇒ $=\frac{2\times 3.14}{0.85}$

⇒ $= \frac{6.28}{0.85}$

⇒ $=7.38 \ rad/s^2$

The centripetal acceleration will be:

⇒ $a=r\times w^2$

⇒ $=0.40\times (7.38)^2$

⇒ $=0.40\times 54.46$

⇒ $=21.785 \ m/s^2$

7 0

2 years ago