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8090 [49]
3 years ago
15

How much kinetic energy does a 50 kg rock has if its moving at a velocity of 2m/s

Physics
1 answer:
maria [59]3 years ago
5 0

Answer:

KE = 100 J

Explanation: Should be correct

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Which of the following is an example of a renewable natural resource?
borishaifa [10]

Answer:

c. lumber      

Explanation:

Lumber is considered a renewable natural resource because it is gotten from trees and trees are grow-able. A renewable natural resource is a resource which can be used repeatedly and replaced naturally. Examples of renewable natural resources are solar energy from the sun, water, oxygen, biomass, trees etc. Trees can be harvested and processed into lumber. The harvested trees can be planted again by humans or they can naturally reproduce through seedlings or fruits that drop and germinate on their own. This renewable germinating process of trees makes lumber a renewable natural resource.

6 0
3 years ago
A greyhound's velocity changes from rest to 19 m/s in 2 seconds. What is the greyhound's average acceleration?
Andrew [12]

It should be b)9.5m/s2

6 0
3 years ago
Paul’s 10 kg baby sister Susan sits on a mat. Paul pulls the mat across the floor using a rope that is angled 30° above the floo
kiruha [24]

Answer:

The speed of Susan is 2.37 m/s

Explanation:

To visualize better this problem, we need to draw a free body diagram.

the work is defined as:

W=F*d*cos(\theta)

here we have the work done by Paul and the friction force, so:

W_p=F_p*d*cos(0)\\F_p=30N*cos(30^o)=26N\\W_p=26*3*(1)=78J

W_f=F_f*d*cos(180)\\F_f=\µ*(10*9.8-30N*sin(30^o))=16.6N\\W_p=16.6*3*(-1)=50J

Now the change of energy is:

W_p-W_f=\frac{1}{2}m*v^2\\v=\sqrt{\frac{2(78J-50J)}{10kg}}\\v=2.37m/s

4 0
3 years ago
Read 2 more answers
Suppose the initial kinetic energy and final potential energy in an experiment are both zero. What can you conclude?
Kisachek [45]

Initially, the experiment has only potential energy (since total energy is the sum of kinetic and potential energy). And at the end, the experment has only kinetic energy.

5 0
3 years ago
On level ground a shell is fired with an initial velocity of 49.0 m/s at 70.0 โ above the horizontal and feels no appreciable ai
xenn [34]

Answer:

Horizontal component = 16.8 m/s

Vertical component = 46.0 m/s

Explanation:

If we denote the initial velocity by <em>v</em> and the angle above the horizontal by <em>θ</em>,

the horizontal component of this initial velocity is given by

v_x = v\cos \theta

v_x = (49.0\text{ m/s})\cos\,(70.0^\circ) = 16.8\text{ m/s}

The vertical component is given by

v_y = v\sin\theta

v_x = (49.0\text{ m/s})\sin\,(70.0^\circ) = 46.0\text{ m/s}

3 0
3 years ago
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