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3 years ago

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What is the mass, in grams, of a sample of 6.12 × 10^24 atoms of manganese (Mn)? Show your work or explain the steps that you us

ed to determine your answer.

1 answer:

e-lub [12.9K]3 years ago

6 0

<span>6.12<span>(<span>1024</span>)</span></span><span>=<span><span>(6.12)</span><span>(<span><span>1e</span>+24</span>)</span></span></span><span>=<span><span>6.12e</span>+24</span></span> <span> = </span>

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An example of a physical property of an element is the element's ability to

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The net ionic equation for the given reaction :

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Replacing $MnI_2(aq)$ , NaI and $Na_3PO_4(aq)$ in [1] by usig [2] [3] and [4]

$3Mn^{2+}(aq)+6I^-(aq)+6Na^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)+6Na^+(aq)+6I^-(aq)$

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

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3 years ago

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So, $116.8kPa(\frac{1aym}{101.325kPa})$

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3 years ago

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I hope this helps :)

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3 years ago